Part 1
Part 2
Part 3
Part 4
Part 5
![[(2-3)^2-5]\cdot4=[(-1)^2-5]\cdot4 \\ \\ =(1-5)\cdot4=-4\cdot4=-16](https://tex.z-dn.net/?f=%5B%282-3%29%5E2-5%5D%5Ccdot4%3D%5B%28-1%29%5E2-5%5D%5Ccdot4%20%5C%5C%20%20%5C%5C%20%3D%281-5%29%5Ccdot4%3D-4%5Ccdot4%3D-16)
Part 6
Part 7
Part 8
Part 9
![(8-2)^2+\frac{1}{4}[4-3(6-10)]=6^2+\frac{1}{4}[4-3(-4)] \\ \\ =36+\frac{1}{4}[4-(-12)]=36+\frac{1}{4}(4+12)=36+\frac{1}{4}(16) \\ \\ =36+4=40](https://tex.z-dn.net/?f=%288-2%29%5E2%2B%5Cfrac%7B1%7D%7B4%7D%5B4-3%286-10%29%5D%3D6%5E2%2B%5Cfrac%7B1%7D%7B4%7D%5B4-3%28-4%29%5D%20%5C%5C%20%20%5C%5C%20%3D36%2B%5Cfrac%7B1%7D%7B4%7D%5B4-%28-12%29%5D%3D36%2B%5Cfrac%7B1%7D%7B4%7D%284%2B12%29%3D36%2B%5Cfrac%7B1%7D%7B4%7D%2816%29%20%5C%5C%20%20%5C%5C%20%3D36%2B4%3D40)
Part 10
Part 11
![3-2[2^3+(-1)^3]=3-2[8+(-1)] \\ \\ =3-2(8-1)=3-2(7)=3-14 \\ \\ -11](https://tex.z-dn.net/?f=3-2%5B2%5E3%2B%28-1%29%5E3%5D%3D3-2%5B8%2B%28-1%29%5D%20%5C%5C%20%20%5C%5C%20%3D3-2%288-1%29%3D3-2%287%29%3D3-14%20%5C%5C%20%20%5C%5C%20-11)
Part 12
Part 2
Part 3
Part 4
Part 5
Part 6
Part 7
Part 8
Part 9
Part 10
Part 11
Part 12
Can someone please answer. There is one problem. There is a picture. Thank you!!
1 answer:
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