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3 years ago

8

Determine the x- and y-intercepts of the graph of y = 1/4x - 2 .

1 answer:

OLga [1]3 years ago

7 0

Answer:

its 65

Step-by-step explanation:

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A lid on a circular container has a diameter of 9 cm. What is the approximate area of the lid? Use 3.14 to approximate pi and ro

kkurt [141]

Area=pir^2

diameter/2=radius
diameter=9
d/2=9/2=4.5=r

area=pi4.5^2
area=pi20.25
aproxpi=3.14
area=63.585
round hundreth
area=63.59

answer is 63.59cm^2

7 0

3 years ago

Read 2 more answers

Show that every triangle formed by the coordinate axes and a tangent line to y = 1/x ( for x > 0)

vfiekz [6]

Answer:

Step-by-step explanation:

given a point $(x_0,y_0)$ the equation of a line with slope m that passes through the given point is

$y-y_0 = m(x-x_0)$ or equivalently

$y = mx+(y_0-mx_0)$ .

Recall that a line of the form $y=mx+b$ , the y intercept is b and the x intercept is $\frac{-b}{m}$ .

So, in our case, the y intercept is $(y_0-mx_0)$ and the x intercept is $\frac{mx_0-y_0}{m}$ .

In our case, we know that the line is tangent to the graph of 1/x. So consider a point over the graph $(x_0,\frac{1}{x_0})$ . Which means that $y_0=\frac{1}{x_0}$

The slope of the tangent line is given by the derivative of the function evaluated at $x_0$ . Using the properties of derivatives, we get

$y' = \frac{-1}{x^2}$ . So evaluated at $x_0$ we get $m = \frac{-1}{x_0^2}$

Replacing the values in our previous findings we get that the y intercept is

$(y_0-mx_0) = (\frac{1}{x_0}-(\frac{-1}{x_0^2}x_0)) = \frac{2}{x_0}$

The x intercept is

$\frac{mx_0-y_0}{m} = \frac{\frac{-1}{x_0^2}x_0-\frac{1}{x_0}}{\frac{-1}{x_0^2}} = 2x_0$

The triangle in consideration has height $\frac{2}{x_0}$ and base $2x_0$ . So the area is

$\frac{1}{2}\frac{2}{x_0}\cdot 2x_0=2$

So regardless of the point we take on the graph, the area of the triangle is always 2.

6 0

3 years ago

Suppose that the value of a stock varies each day from $13 to $24 with a uniform distribution. (a) Find the probability that the

bogdanovich [222]

Answer:

a. P= 0.6364

b. P = 0.3636

c. Q = $21.25

d. P = 0.5

Step-by-step explanation:

given data

value of a stock varies = $13 to $24

solution

P (stock value is more than $17)

P = $\frac{(24-17)}{(24-13)}$

P = $\frac{7}{11}$

P = 0.6364

and

P (value of the stock is between $17 and $21)

P = $\frac{(21-17)}{(24-13)}$

P = $\frac{4}{11}$

P = 0.3636

and

Let the upper quartile be Q

$\frac{(24 - Q)}{(24 - 13)} = 0.25$

$\frac{(24 - Q)}{11} = 0.25$

(24 - Q) = 2.75

so

Q = $21.25

and

P(X > 20 | X > 16)

P = $\frac{(24-20)}{(24-16)}$

P = $\frac{4}{8}$

P = 0.5

3 0

3 years ago

Identify the area of segment MNO to the nearest hundredth. HELP PLEASE!!

insens350 [35]

The area of a right triangle with side lengths 7 and 7 is $\frac{bh}{2} = \frac{7*7}{2} = \frac{49}{2} = 24.5$

4 0

3 years ago

Part 2 to that question answer right pls

Marta_Voda [28]

Answer:

1. decreases

2. 31.50

Step-by-step explanation:

It decreases because there's a negative sign.

It's 31.50 because 10.50 * 3 = 31.50

4 0

2 years ago

Read 2 more answers