What is the slope of the line in this graph?
1 answer:
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Answer:
Solution given:
BD=35ft
AC=43ft
AB=8ft
EF=33-8=25ft
AE=26ft
Now
area of right angled triangle ∆AEF
=½(EF*AE)=½(25×25)=312.5ft²
area of parallel trapezoid=½AB(BD+AC)
=½*8(35+43)=312ft²
<u>So</u>
<u>Area</u><u> </u><u>of</u><u> </u><u>polygon</u><u> </u><u>:</u><u> </u><u>3</u><u>1</u><u>2</u><u>.</u><u>5</u><u>+</u><u>3</u><u>1</u><u>2</u><u>=</u><u>6</u><u>2</u><u>4</u><u>.</u><u>5</u><u>f</u><u>t</u><u>²</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u><u>.</u>
