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Ipatiy [6.2K]
3 years ago
12

Simplify 8 plus 4 squared minus 3(7) plus 3 squared

Mathematics
1 answer:
Masteriza [31]3 years ago
3 0
8+4^2-3(7)+3^2
8+16-3(7)+9
8+16-21+9
24-21+9
3+9
=12
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I don't know how to do this one. plz help
egoroff_w [7]

Answer:

As x decreases without bound, f(x) increases without bound

As x increases without bound, f(x) approaches 0

Step-by-step explanation:

As x gets more and more negative f(x)  gets bigger and bigger

f(x) = (7/10) ^ x but x is negative  so flip it and then x is a larger number

       (10/7) ^  large number   so it will get larger

 as → -∞   f(x) →∞    


As x gets more and more positive f(x)  gets smaller and smaller

f(x) = (7/10) ^ x   closer and closer to 0.  The denominator gets larger faster than the numerator  = 1 / large number

       

 as → ∞   f(x) →0    

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2 years ago
The original price for a jacket was 124.95. It is on sale for 20% off. Witch of the following gives the best estimate of the sav
d1i1m1o1n [39]
20% of 124.95 is close to $125 so that is equal of 12.50 of 10% so multiply by 2 which is $25.00 so the estimate discount of the jacket will be $25.00
7 0
3 years ago
Read 2 more answers
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Alexxandr [17]
A number cube is a die (singular for dice). List all of the possible outcomes of a die (list numbers of 1 to 6), and next to those numbers, determine if they are even or odd.
8 0
2 years ago
I’m Really lost if I could get a answer it would be greatly appreciated
Nataly [62]
<h3>Answers:</h3>

f(g(x)) = \sqrt{x^2+5}+5\\\\g(f(x)) = x+30+10\sqrt{x-1}

================================================

Work Shown:

Part 1

f(x) = \sqrt{x-1}+5\\\\f(g(x)) = \sqrt{g(x)-1}+5\\\\f(g(x)) = \sqrt{x^2+6-1}+5\\\\f(g(x)) = \sqrt{x^2+5}+5\\\\

Notice how I replaced every x with g(x) in step 2. Then I plugged in g(x) = x^2+6 and simplified.

------------------

Part 2

g(x) = x^2+6\\\\g(f(x)) = \left(f(x)\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}+5\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}\right)^2+2*5*\sqrt{x-1}+\left(5\right)^2+6\\\\g(f(x)) = x-1+10\sqrt{x-1}+25+6\\\\g(f(x)) = x+30+10\sqrt{x-1}\\\\

In step 4, I used the rule (a+b)^2 = a^2+2ab+b^2

In this case, a = sqrt(x-1) and b = 5.

You could also use the box method as a visual way to expand out \left(\sqrt{x-1}+5\right)^2

6 0
3 years ago
Pleas help me out here.
Amiraneli [1.4K]

Answer:

A and E

Step-by-step explanation:

The given problem shows a graph of a vertical line with an undefined slope, in which its equation is x = 3 (which matches Option A).

It is not considered a function because it has the same input for every given output.  This means that regardless of its y-coordinate, its corresponding x-coordinate will always be x = 3.  

The Vertical Line Test allows us to know whether or not a graph is actually a function. Remember that a function can only take on one output for each input. We cannot plug in a value and produce two output values.  Since the graph represents a vertical line, it automatically fails the vertical line test. Therefore, it is not a function.

Because it is not a function, Options B, C, and D are invalid answers.

Hence, the correct answers are Options A and E.

4 0
2 years ago
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