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max2010maxim [7]

3 years ago

5

Write 5 equivalent ratios to the given ratio 5/7

1 answer:

slavikrds [6]3 years ago

4 0

Answer:

Step-by-step explanation: both times 2 equals 10/14 times 3 = 15/21 times 4 is 20/28

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Which equation is equivalent to 7-2(3x+4)=8x <br> A -6x+15=8x<br> B-6x-1=8x<br> C15x+20=8x

Reptile [31]

Answer:

B

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Given that F(x) = x 2 + 2, evaluate F(2).<br> 0<br> 2<br> 6

belka [17]

Answer 6

2^2+2
4+2=6
Got it

4 0

4 years ago

Read 2 more answers

How to get slope from standard form.

lidiya [134]

Answer:

Solve the equation for y. See example.

Step-by-step explanation:

I'll use 3x + 5y = 15. First subtract 3x from both sides since it is positive.

$3x + 5y = 15 \\ - 3x \: \: \: \: \: \: \: \: \:\: \: \: \: \: \: - 3x$

$5y = - 3x + 15$

Now solve for y by dividing each term by 5.

$\frac{5y}{5} = \frac{ - 3}{5} x + \frac{15}{5}$

Now simplify.

$y = \frac{ - 3}{5} x + 3$

The slope is

$- \frac{3}{5}$

5 0

3 years ago

A school sells tickets to its annual Winter Wonderland event and earns $80 for selling 50 tickets. Each ticket was the same pric

Readme [11.4K]

Answer:

$1.60

Step-by-step explanation:

You can divide 80/50 and you will get how much each ticket costs.

7 0

3 years ago

A magician’s stage has a rectangle trapdoor which is (x+ 1/2) by 2x ft. The outside rectangle length is (x+ 16) ft.

Katen [24]

Answer:

Part A:- $x +11 ft$ Part B:- $(4x+54)ft$ part C:- $x= 2ft$

Part D:- Yes it satisfy his requirement

Step-by-step explanation:

Given that,

length and breadth of Trapdoor are $(x+ \frac{1}{2} ) by 2x$ ft.

The Outside length of Rectangle is $(x+16 )$ ft.

Part A:- Total area (in square feet) of the stage can be represented by

$x^{2} + 27x+ 176$ . Write an expression for the width of stage.

So, Area of rectangle = $length \times breadth$

$x^{2} + 27x+ 176 = (x+16) \times breadth$

$Breadth = \frac{x^{2} + 27x+ 176}{x+16}$

$Breadth = x+11$ ft. ................(1)

Part B:- Write an expression for the Perimeter of the stage.

Here, Perimeter of Rectangle = $2(L+B)$

= $2(x+16 + x +11)$

= $(4x + 54) ft$

Part C:- The area of trapdoor is $10 ft^{2}$ . Find the value of x.

So, Area of trapdoor = $10 ft^{2}$

$(x +\frac{1}{2}) \times 2x =10 ft^{2}$

$2x^{2} +x - 10 = 0$

$x = \frac{-1-9}{4}$ , $\frac{-1+9}{4}$

$x = \frac{-5}{2}$ , $2$

Hence value of x is $2 ft$ (Neglecting the negative value because

length cannot be negative).

Part D:- The magician wishes to have the area of the stage be at least 20 times the area of the trapdoor. Does this stage satisfy his requirement? Explain.

So, Length of trapdoor is $(2+\frac{1}{2} ) = \frac{5}{2} ft$

breadth of trapdoor is $2\times 2 = 4ft$

Now, outside length of Rectangle is = $18ft$

And outside breadth of rectangle is = $13ft$

Here, Area of trapdoor = $\frac{5}{2} \times 4 = 10ft^{2}$ ...................(2)

Area of rectangle = $18 \times 13= 234 ft^{2}$ ....................(3)

Thus comparing Equation (1) & (2) we found that

Area of rectangular stage is 20 times greater than the area of trapdoor.

7 0

4 years ago