Answer:
0.1019
Step-by-step explanation:
Probability, p=12%=0.12
Sample size, n=130 students
Those writing with left=14 students
Using the formula for binomial distribution
P(X≤x)=![\left[\begin{array}{}n\\x\end{array}\right]p^{x}(1-p)^{n-x}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7B%7Dn%5C%5Cx%5Cend%7Barray%7D%5Cright%5Dp%5E%7Bx%7D%281-p%29%5E%7Bn-x%7D)
Substituting 0.12 for p, 130 for n, 14 for x we obtain
P(X≤x)=![\left[\begin{array}{}130\\14\end{array}\right]0.12^{14}(1-0.12)^{130-14}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7B%7D130%5C%5C14%5Cend%7Barray%7D%5Cright%5D0.12%5E%7B14%7D%281-0.12%29%5E%7B130-14%7D)
P(X≤x)=
P(X≤x)=0.1019
I wish i knew but i need points sorry
Flip your chicken strips! hadalpealic - -6 km and dp
Answer:
D) 4.01 miles
Step-by-step explanation:
2.87 miles from Monday + 1.14 miles =4.01 ran on Tuesday
Answer:
the question is incomplete, so I looked for a similar one:
<em>After the release of radioactive material into the atmosphere from a nuclear power plant, the hay was contaminated by iodine 131 ( half-life, 8 days). If it is all right to feed the hay to cows when 10% of the iodine 131 remains, how long did the farmers need to wait to use this hay? </em>
iodine's half life (we are given x, we need to find b):
0.5A₀ = A₀eᵇˣ
x = 8 days
we eliminate A₀ from both sides
0.5 = eᵇ⁸
ln 0.5 = ln eᵇ⁸
-0.69315 = b8
b = -0.69315 / 8 = -0.08664
since the farmers need to wait until only 10% of the iodine remains (we already calculated b, now we need to find x):
0.1A₀ = A₀eᵇˣ
0.1 = eᵇˣ
ln 0.1 = bx
where b = -0.08664
x = ln 0.1 / -0.08664 = -2.302585 / -0.08664 = 26.58 days
