20 POINTS FOR FIRST PART AND 20 POINTS FOR THE SECOND PART
1 answer:
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Answer:
27:9:9:9:3:3:3:1
Explanation:
The gametes of the parental genotypes would be
ABC, ABc, AbC, aBC, Abc, aBc, abC, abc
The cross between AaBbCc and AaBbCc will result into following offspring (image is also attached)
ABC ABc AbC aBC Abc aBc abC abc
ABC AABBCC AABBCc AABbCC AaBBCC AABbCc AaBBCc AaBbCC AaBbCc
ABc AABBCc AABBcc AABbCc AaBBCc AaBbcc AaBBcc AaBbCc AaBbcc
AbC AABbCC AABbCc AAbbCC AaBbCC AAbbCc AaBbCc AabbCC AabbCc
aBC AaBBCC AaBBCc AaBbCC aaBBCC AaBbCc aaBBCc aaBbCC aaBbCc
Abc AABbCc AABbcc AAbbCc AaBbCc AAbbcc AaBbcc AabbCc Aabbcc
aBc AaBBCc AaBBcc AaBbCc aaBBCc AaBbcc aaBBcc aaBbCc aaBbcc
abC AaBbCC AaBbCc AabbCC aaBbCC AabbCc aaBbCc aabbCC aabbCc
abc AaBbCc AaBbcc AabbCc aaBbCc Aabbcc aaBbcc aabbCc aabbcc
The genotype ratio is 27:9:9:9:3:3:3:1
