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SSSSS [86.1K]
3 years ago
12

What is the formula to find momentum

Physics
1 answer:
kvv77 [185]3 years ago
3 0
<span>P=mv

Momentum of any object is defined as the multiple of velocity of an object and the mass of the object. So we can easily deduce that momentum is directly proportional to velocity of an object if the mass of the object remains constant. So it can be seen that if the mass of the object does not change then any change in velocity is bound to have an effect on the momentum of the object. We can easily write the equation as momentum= mass x velocity.<span>
</span></span>
You might be interested in
Which electrode in Thomson’s vacuum tube was positively charged
Taya2010 [7]

Anode

Explanation:

The anode in the gas discharge tube used by Thomson in his experiment was the positively charged electrode.

Using the gas discharge tube, Thomson made the remarkable discovery of cathode rays.

The rays moves from the negatively charged cathode to the positively charged anode. This indicated that the rays carry positive charges.

Some parts of the tube are:

  • Cathode - negatively charged electrode
  • Power source
  • Gas at low pressure
  • Outlet to vacuum pump

Learn more:

cathode brainly.com/question/12747250

#learnwithBrainly

8 0
3 years ago
An amateur golfer swings a golf club, striking a golf ball that has a mass of 55.0 g. The club is in contact with the ball for o
Rudiy27

Answer:

The average force ≅ 519.44 N.

Explanation:

Impulse = change in momentum of a body

i.e Ft = m(v - u)

where F is the force, t is the time, m is the mass of the body, v is the final velocity and u is the initial velocity.

m = 55.0 g (0.055 Kg), t = 0.00360 s, v = 34.0 m/s, since the ball was initially at rest; u = 0 m/s

So that,

F x 0.00360 = 0.055(34 - 0)

F x 0.00360 = 0.055 x 34

                    = 1.87

F = \frac{1.87}{0.0036}

 = 519.4444

The average force exerted on the ball by the club is approximately 519.44 N.

4 0
3 years ago
The sum of two component vectors is referred to as the
blondinia [14]
Resultant is the correct answer!
8 0
2 years ago
a swimmer can swim in still water at a speed of 9.50 m/s. he intends to swim directly across the river that has a downstream cur
Doss [256]
Refer to the diagram shown below.

Still-water speed  = 9.5 m/s
River speed = 3.75 m/s down stream.

The velocity of the swimmer relative to the bank is the vector sum of his still-water speed and the speed of the river.

The velocity relative to the bank is
V = √(9.5² + 3.75²) = 10.21 m/s

The downstream angle is
θ = tan⁻¹ 3.75/9.5 = 21.5°

Answer:  10.2 m/s at 21.5° downstream.

7 0
3 years ago
Read 2 more answers
QUESTION 10
Elena L [17]

The maximum value of θ of such the ropes (with a maximum tension of 5,479 N) will be able to support the beam without snapping is:

\theta =37.01^{\circ}

We can apply the first Newton's law in x and y-direction.

If we do a free body diagram of the system we will have:

x-direction

All the forces acting in this direction are:

T_{1}sin(\theta)-T_{2}sin(\theta)=0    (1)

Where:

  • T(1) is the tension due to the rope 1
  • T(2) is the tension due to the rope 2

Here we just conclude that T(1) = T(2)

y-direction

The forces in this direction are:

T_{1}cos(\theta)+T_{2}cos(\theta)-W=0   (2)

Here W is the weight of the steel beam.

We equal it to zero because we need to find the maximum angle at which the ropes will be able to support the beam without snapping.

Knowing that T(1) = T(2) and W = mg, we have:

T_{1}cos(\theta)+T_{1}cos(\theta)-m_{steel}g=0

2T_{1}cos(\theta)-m_{steel}g=0

2T_{1}cos(\theta)=m_{steel}g

T(1) must be equal to 5479 N, so we have:

cos(\theta)=\frac{m_{steel}g}{2T_{1}}

cos(\theta)=\frac{892*9.81}{2*5479}

cos(\theta)=\frac{892*9.81}{2*5479}

cos(\theta)=0.80

Therefore, the maximum angle allowed is θ = 37.01°.

You can learn more about tension here:

brainly.com/question/12797227

I hope it helps you!

8 0
3 years ago
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