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Svetllana [295]
3 years ago
6

A classroom is about 3 meters high, 20 meters wide and 30 meters long. If the density of air is 1.29 kg/m3, what is the mass of

the air in the classroom?
Physics
2 answers:
Deffense [45]3 years ago
8 0

Answer:

the mass of the air in the classroom = 2322 kg

Explanation:

given:

A classroom is about 3 meters high, 20 meters wide and 30 meters long.

If the density of air is 1.29 kg/m3

find:

what is the mass of the air in the classroom?

density = mass / volume

where mass (m) = 1.29 kg/m³

volume = 3m x 20m x 30m = 1800 m³

plugin values into the formula

  1.29 kg/m³   =  <u>      mass    </u>

                             1800 m³

mass =  1.29 kg/m³  ( 1800 m³ )

mass = 2322 kg

therefore,

the mass of the air in the classroom = 2322 kg

viva [34]3 years ago
3 0

_______________________________________

Extra info related to the question :-

What is a rationlising factor ?

If the product of two irrational numbers is a rational number then each of the the two is rationalising factor of the other.

What is the purpose of rationilising the denominator ?

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3 years ago
A 0.76-kg block is hung from and stretches a spring that is attached to the ceiling. A second block is attached to the first one
sergey [27]

Answer:

1.54 kg

Explanation:

mass of first block (m) = 0.76 kg

acceleration due to gravity (g) = 9.8 m/s

what is the mass (m) of the second block

  • force = kx ⇒ mg = kx

        mg = kx

        where m is the mass, g is the acceleration due to gravity, k is the  

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        0.76 x 9.8 = kx

       7.5 = kx

        k = 7.5/x ... equation 1

  • when a second block is attached to the first one the amount of stretch triples (this means that extension (x) = 3x)

        therefore the new mass becomes m + 0.76 and the extension  

        becomes 3x

        with the new mass and extension, mg = kx now becomes

        (m+0.76)g = k(3x) ... equation 2

        Recall that k = 7.5/x from equation 1, substituting this value of k into      

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         (m+0.76)g =  \frac{7.5}{x} × (3x)

         (m+0.76)g =  7.5 × 3

          substituting the value of g = 9.8 m/s^{2}

         (m + 0.76) x 9.8 = 7.5 x 3

          m + 0.76 = 22.5 ÷ 9.8

          m + 0.76 = 2.3

          m = 2.3 - 0.76 = 1.54 kg

       

         

       

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How does Photosynthesis use solar energy?
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The answer is D.
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A hot iron horseshoe (mass = 0.35 kg ), just forged, is dropped into 1.40 L of water in a 0.45 kg iron pot initially at 22.0°C.
olga_2 [115]

Answer:

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Explanation:

m_{h} = mass of the horseshoe = 0.35 kg

m_{w} = mass of the water = 1.40 L = 1.40 kg

m_{i} = mass of the iron pot = 0.45 kg

c_{i} = specific heat of iron = 450 J kg⁻¹ °C⁻¹

c_{w} = specific heat of water = 4186 J kg⁻¹ °C⁻¹

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T_{wi} = initial temperature of the water = 22 °C

T_{pi} = initial temperature of the iron pot = 22 °C

T_{f} = final temperature = 32 °C

Using conservation of Heat

m_{h}c_{i}(T_{hi} - T_{f}) = m_{w}c_{w}(T_{f} - T_{wi}) + m_{i}c_{i}(T_{f} - T_{pi})

(0.35)(450)(T_{hi} - 32) = (1.40)(4186)(32 - 22) + (0.45)(450)(32 - 22)

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The only difference between the speed and the velocity is that the velocity tell us about magnitude and direction but speed tell us about magnitude only.

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6 0
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