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Svetllana [295]
3 years ago
6

A classroom is about 3 meters high, 20 meters wide and 30 meters long. If the density of air is 1.29 kg/m3, what is the mass of

the air in the classroom?
Physics
2 answers:
Deffense [45]3 years ago
8 0

Answer:

the mass of the air in the classroom = 2322 kg

Explanation:

given:

A classroom is about 3 meters high, 20 meters wide and 30 meters long.

If the density of air is 1.29 kg/m3

find:

what is the mass of the air in the classroom?

density = mass / volume

where mass (m) = 1.29 kg/m³

volume = 3m x 20m x 30m = 1800 m³

plugin values into the formula

  1.29 kg/m³   =  <u>      mass    </u>

                             1800 m³

mass =  1.29 kg/m³  ( 1800 m³ )

mass = 2322 kg

therefore,

the mass of the air in the classroom = 2322 kg

viva [34]3 years ago
3 0

_______________________________________

Extra info related to the question :-

What is a rationlising factor ?

If the product of two irrational numbers is a rational number then each of the the two is rationalising factor of the other.

What is the purpose of rationilising the denominator ?

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Anettt [7]

Answer:

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Explanation:

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Where u’ is the speed with respect to the mobile system, in this case the initial nucleus of uranium, u the speed with respect to the fixed system (the observer in the laboratory) and v the speed of the mobile system with respect to the laboratory

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Let's clear the speed with respect to the observer (u)

      u’ (1- u v / c²) = u -v

      u + u ’uv / c² = v - u’

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Let's calculate

      u = (0.94 c - 0.43c) / (1+ 0.43c 0.94 c / c²)

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We repeat the calculation for the other piece

In this case u ’= - 0.35c

We calculate

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6 0
3 years ago
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Answer:

1.56\times 10^5 N/C        

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Substitute the values:

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6 0
3 years ago
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Anna [14]

Answer:

f= 440.4 Hz or f= 439.6 Hz

Explanation:

In this exercise we have two waves with slightly different frequencies, the A4 chord with f = 440 Hz and the beating with the central chord fbeats = 0.40 Hz, let's use the relation

               f_{beat} = | f - f₀ |

               f = fo + - f _{beat}

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8 0
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liubo4ka [24]

my sis just took the test the answer is

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4 0
3 years ago
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Aliun [14]

Answer:

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Explanation:

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Where:

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x - Deformation of the spring, measured in meters.

If we know that k = 865\,\frac{N}{m} and x = 0.065\,m, then the elastic potential energy is:

U_{g} = \frac{1}{2}\cdot \left(865\,\frac{N}{m} \right) \cdot (0.065\,m)

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b) According to the Principle of Energy Conservation, the initial elastic potential energy of the block-spring system becomes into translational kinetic energy, that is:

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Then, the final speed is cleared:

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If we know that U_{g} = 28.113\,J and m = 3.20\,kg, then the final speed of the block is:

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The final speed of the block is approximately 4.192 meters per second.

3 0
3 years ago
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