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Korolek [52]
3 years ago
6

Sunshine Corporation is expected to pay a dividend of $1.50 in the upcoming year. Dividends are expected to grow at the rate of

6% per year. The risk-free rate of return is 6%, and the expected return on the market portfolio is 14%. The stock of Sunshine Corporation has a beta of 0.75. The intrinsic value of the stock is
Physics
2 answers:
grigory [225]3 years ago
7 0

Answer:

$25

Explanation:

The computation of the intrinsic value of the stock is shown below:

As we know that

Intrinsic value or Price = Dividend ÷ (Cost of equity - growth rate)

where,

Cost of equity or ke  is

= Risk free rate of return  + beta × (Market rate of return - risk free rate of return)

= 6% + 0.75 × (14% - 6%)

= 12 %

So the intrinsic value is

= $1.50 ÷ (12% - 6%)

= $25

Karo-lina-s [1.5K]3 years ago
7 0

Answer:

7.82

Explanation:

because the percentage is too low

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Describe how personal fitness contributes to physical,mental/emotional,social health
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When you work out it helps clear your thoughts and think of nothing. It makes you feel good.
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3 years ago
a radio station broadcast a frequency 90500 Hz. these radio waves travel at speed of 30000 m/s. what is the wavelength of the ra
Feliz [49]

Answer:

0.331m

Explanation:

wave equation: v=f λ

v=30000m/s

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λ= \frac{v}{f}

λ= \frac{30000}{90500}

λ= 0.311m

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2 years ago
Unpolarized light with intensity I0I0I_0 is incident on an ideal polarizing filter. The emerging light strikes a second ideal po
zvonat [6]

Answer:

0.293I_0

Explanation:

When the unpolarized light passes through the first polarizer, only the component of the light parallel to the axis of the polarizer passes through.

Therefore, after the first polarizer, the intensity of light passing through it is halved, so the intensity after the first polarizer is:

I_1=\frac{I_0}{2}

Then, the light passes through the second polarizer. In this case, the intensity of the light passing through the 2nd polarizer is given by Malus' law:

I_2=I_1 cos^2 \theta

where

\theta is the angle between the axes of the two polarizer

Here we have

\theta=40^{\circ}

So the intensity after the 2nd polarizer is

I_2=I_1 (cos 40^{\circ})^2=0.587I_1

And substituting the expression for I1, we find:

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5 0
2 years ago
Light is shone on a diffraction grating
Pani-rosa [81]

Answer:

    λ = 482.05 nm

Explanation:

The diffraction phenomenon and the diffraction grating is described by the expression

         d sin θ = m λ

where d is the distance between two consecutive slits, λ the wavelength and m an integer representing the order of diffraction

in this case they indicate the distance between slits, the angle and the order of diffraction

         λ = \frac{d sin \theta }{m}d sin θ / m

let's calculate

         λ = 1.00 10⁻⁶ sin 74.6 / 2

         λ = 4.82048 10⁻⁷ m

Let's reduce to nm

         λ = 4.82048 10⁻⁷ m (10⁹ nm / 1 m)

         λ = 482.05 nm

3 0
2 years ago
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