Consider the length of diagonal is 8.5 cm instead of 8.5 m because length of perpendiculars are in cm.
Given:
Length of the diagonal of a quadrilateral = 8.5 cm
Lengths of the perpendiculars dropped on it from the remaining opposite vertices are 3.5 cm and 4.5 cm.
To find:
The area of the quadrilateral.
Solution:
Diagonal divides the quadrilateral in 2 triangles. If diagonal is the base of both triangles then the lengths of the perpendiculars dropped on it from the remaining opposite vertices are heights of those triangles.
According to the question,
Triangle 1 : Base = 8.5 cm and Height = 3.5 cm
Triangle 2 : Base = 8.5 cm and Height = 4.5 cm
Area of a triangle is
Using this formula, we get
and
Now, area of the quadrilateral is
Therefore, the area of the quadrilateral is 34 cm².
Answer:
x=-1
y=-1
Step-by-step explanation:
-6x + 5y =1 ......equation (1)
6x + 4y = –10 ......equation (2)
adding equation (1) to equation (2)
9y=-9
9y/9 =-9/9 (dividing both side by the coefficient of y)
y=-1
subtituting the value of y =-1 into equation (2)
6x+4(-1)=-10
6x+(-4)=-10
6x-4=-10
6x=-10+4(making constant to be at one side and the variable at the other side)
6x=-6
x=-6/6
x=-1
Answer:
Step-by-step explanation:
A. Walk down 10 steps
B. Cool down 10 degrees
C. Travel north 10 km
D. Spend 6 dollars
F. Run forward 9 steps
42,500x0.09 should get you your commission
Answer:
(-5 , 1)
Step-by-step explanation:
If you are reflecting over the x-axis, you are changing the sign of the y.
If you are reflecting over the y-axis, you are changing the sign of the x.
In this case, you have the point (5 , 1). You are reflecting over the y-axis, which means that you are flipping the sign of the x value.
(5 , 1) reflected over the y-axis is (-5 , 1)
(-5 , 1)
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