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Wittaler [7]
4 years ago
5

Jane andre and maria pick apples .Andre picks three times as many pounds as maris .Jane picks two times as .A u pounds as andre

.Tbw total weight of tbe apples is 840 pounds .How maby pounds of apples dose andre pick?
Mathematics
1 answer:
spayn [35]4 years ago
7 0

Answer: Andre picked 252 pounds of apples

Step-by-step explanation:

Let x = number of pounds of apple picked by Jane.

Let y = number of pounds of apple picked by Andre

Let z = number of pounds of apple picked by Maria

Andre picks three times as many pounds as maria. It means that

y = 3z

Jane picks two times as many pounds as Andre. It means that

x = 2y

The total weight of the apples is 840 pounds. It means that

x + y + z = 840 - - - - - - - - - 1

We will substitute z = y/3 and x = 2y into equation 1

2y + y + y/3 = 840

Cross multiplying with 3

6y + 3y + y = 2520

10y = 2520

y = 2520/10 = 252

x = 2y = 252× 2 = 504

z = y/3 = 252/3 = 84

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Answer:

A = £7.15 per hour

James' average pay per hour this year is £7.15 per hour

Step-by-step explanation:

Given;

Last year pay = £1,100 per month

This year, he's had a 4% increase in his monthly pay

This year pay P = 1,100 + 4% of 1,100 = 1,100 +1,100(0.04)

This year pay P = £1,144 per month

Yearly pay Tp= 12 × P = 12 × £1,144 = £13,728

Number of hours worked this year;

He worked 40 hours per week for 48 weeks in the year

N = 40 hours per week × 48 weeks per year

N = 1920 hours per year

Average pay per hour this year A;

A = Yearly pay/Number of hours worked this year

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A = £13,728/1920hours

A = £7.15 per hour

James' average pay per hour this year is £7.15 per hour

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Answer:

The set A={(1,2),(2,2),(3,2),(4,2),(5,2),(6,2),(1,4),(2,4),(3,4),(4,4),(5,4),(6,4),(1,(2,6),(3,6),(4,6),(5,6),(6,6)}

B={(2,2),(4,2),(6,2),(2,4),(2,6),(1,3),(1,5),(1,1),(3,1),(3,3),(3,5),(4,4),(4,6),(5,1),(5,3),(5,5),(6,4),(6,6)}

C={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,3),(2,5),(3,3),(3,5),(3,4),(3,6),(4,1),(4,3),(4,5),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,3),(6,5)}.

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A∪B={(1,2),(2,2),(4,2),(6,2),(2,4),(2,6),(4,4),(4,6),(6,4),(6,6),(3,2),(5,2),(1,4),(3,4),(5,4),(1,6),(3,6),(5,6),(1,3),(1,5),(1,1)(3,1),(3,3),(3,5),(5,1),(5,3),(5,5)}

A∩C={(1,2),(1,4),(1,6),(3,2),(3,4),(3,6),(5,2),(5,4),(5,6)}

Step-by-step explanation:

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