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Wittaler [7]
3 years ago
5

Jane andre and maria pick apples .Andre picks three times as many pounds as maris .Jane picks two times as .A u pounds as andre

.Tbw total weight of tbe apples is 840 pounds .How maby pounds of apples dose andre pick?
Mathematics
1 answer:
spayn [35]3 years ago
7 0

Answer: Andre picked 252 pounds of apples

Step-by-step explanation:

Let x = number of pounds of apple picked by Jane.

Let y = number of pounds of apple picked by Andre

Let z = number of pounds of apple picked by Maria

Andre picks three times as many pounds as maria. It means that

y = 3z

Jane picks two times as many pounds as Andre. It means that

x = 2y

The total weight of the apples is 840 pounds. It means that

x + y + z = 840 - - - - - - - - - 1

We will substitute z = y/3 and x = 2y into equation 1

2y + y + y/3 = 840

Cross multiplying with 3

6y + 3y + y = 2520

10y = 2520

y = 2520/10 = 252

x = 2y = 252× 2 = 504

z = y/3 = 252/3 = 84

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Step-by-step explanation:

6 0
3 years ago
What integer is equivalent to 25^3/2
Andreas93 [3]
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3 years ago
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-2x-5 = 4

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------  ------

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Mars2501 [29]

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3 0
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KATRIN_1 [288]

Answer:

-3x^2+29x-150+\frac{946x^2-341x-756}{x^3+6x^2-3x-5}  is the answer. See steps below.

Step-by-step explanation:

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}\\\\-3x^5+11x^4+33x^3-26x^2-36x-6\\\\\mathrm{and\:the\:divisor\:}x^3+6x^2-3x-5:\\\\\mathrm{Quotient}=\frac{-3x^5}{x^3}=-3x^2\\\\\mathrm{Multiply\:}x^3+6x^2-3x-5\mathrm{\:by\:}-3x^2\:\:\rightarrow\:\:-3x^5-18x^4+9x^3+15x^2\\\\\mathrm{Subtract\:}-3x^5-18x^4+9x^3+15x^2\mathrm{\:from\:}-3x^5+11x^4+33x^3-26x^2-36x-6\mathrm{\:to\:get\:new\:remainder}.\\\\\mathrm{Remainder}=29x^4+24x^3-41x^2-36x-6

=-3x^2+\frac{29x^4+24x^3-41x^2-36x-6}{x^3+6x^2-3x-5}

Repeat the steps and you will reach a point where no further division is possible.

<u />

<u />=-3x^2+29x-150+\frac{946x^2-341x-756}{x^3+6x^2-3x-5}<u />

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3 years ago
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