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iren2701 [21]
3 years ago
14

Find the area of the shaded region 6cm 6cm

Mathematics
1 answer:
Mashutka [201]3 years ago
4 0
Hope this helps! the answer is option (A). if you still don’t understand after looking at my solution feel free to clarify ya

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PLEASE HELP ASAAAAPPPPPP
monitta
The correct answer is A

4 0
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Read 2 more answers
A ball is dropped from a height of 64 feet. Its height, in feet, can be modeled by the function h(t) = -167 + 64, where t is the
Oliga [24]

Answer:

Step-by-step explanation:

Known facts:

  • the ball dropped from a height of 64 feet
  • function h(t) = -16t^{2}  + 64

First question:

  • the ball hits the ground when h(t) = 0, thus we get the equation

                      -16t^{2} +64 = 0\\16t^{2} = 64\\t^{2} =4\\t = 2

     So the ball hits the ground in 2s

Second question

  • to find how long it takes the ball to fall 36 feet, we must set h(t) = 64 - 36 = 28

                      -16t^{2} +64 = 28\\16t^{2} = 36\\t = \frac{6}{4} =1.5s

      So the ball hits the ground in 1.5s

Hope that helps!

3 0
2 years ago
The line l with equation x - 2y + 2 = 0 crosses the y-axis at the point P. The line
Sauron [17]

Answer:

Area of ΔPQR is 28 units²

Step-by-step explanation:

-P is the point with coordinates ( 0, y-intercept for line x-2y+2 =0)

-rearrange the equation in the point-slope form y=mx+b  to find the y coordinate of the point P( 0, b)

x-2y+2 = 0, subtract x and 2 from both sides

-2y = -x-2, divide by -2 both sides

y= (1/2)x +1 so b=1 and P (0, 1)

-Q  is the point with coordinates ( 0, y-intercept for line 3x+y -15 =0)

-rearrange the equation in the point-slope form y=mx+b  to find the y coordinate of the point Q( 0, b)

3x +y -15 =0, subtract 3x and add 15 to both sides

y= -3x +15 so b=15 and Q(0,15)

-R is the intersection of the two lines so is the solution of the system of equations y= (1/2)x +1 and y= -3x +15

(1/2)x +1 =  -3x +15, add 3x and subtract1

(1/2) x+3x = 15-1, combine like terms

(7/2)x = 14 , multiply both sides by 2

7x = 28, divide both sides by 7

x= 4

y= (1/2)x +1 = (4/2) +1 =3 so R(4,3)

- the area of ΔPQR is (base *height)/2

base= 15-1= 14

height = 4

A= (14*4)/2 = 14*2 = 28

6 0
3 years ago
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