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Tatiana [17]
3 years ago
7

For what value of x does 3^2x=9^3x-4

Mathematics
2 answers:
AVprozaik [17]3 years ago
8 0
ANSWER

The value of x for which
{3}^{2x}  =  {9}^{3x - 4}
is
x = 2


EXPLANATION

The given equation is
{3}^{2x}  =  {9}^{3x - 4} .
This is an indicial equation or an exponential equation in x.


We can see that, this time, the variable is in the numerator.


So we need to express both sides of the equation to the same base to obtain,


{3}^{2x}  =  { 3 }^{2(3x - 4)}


Since the base are the same, we can now equate the exponents to get,



2x = 2(3x - 4)


When we divide both sides of the equation by 2, we obtain,


x = 3x - 4


We now group like terms to obtain,


x - 3x =   - 4


We simplify the left hand side to get,


- 2x =  - 4


We finally divide through by negative 2 to obtain,

x = 2
Therefore the correct answer is B.
jek_recluse [69]3 years ago
4 0
The answer is x=2. Hope this helps!!!
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Algebra help?<br><br> 343 = (x/6) ^2/3
Vladimir79 [104]

I can only assume that you meant, "Solve for x:"

Apply the exponent 3/2 to both sides of this equation.  The result will be

     3/2

343 = x/6.    

Multiplying both sides by 6 isolates x:

          3/2

6*343           = x                         Since 7^3 = 343,  the expression for x

                                                  can be rewritten as

           3/2

6*(7^3)          =   x                      which can be further simplified, as follows:


x =  6^(3/2)*7^(9/2), or:

x = 6^(3/2)*7^(8/2)*√7, or

x = 6^(3/2)*7^4*√7

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4 years ago
Find the slope of the line that passes through (10, 2) and (3, 7).
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Answer:

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Step-by-step explanation:

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Is 2y-x/6-4=0 a linear function
noname [10]

A equation of a linear function in a standard form:

Ax + By = C

2y-\dfrac{x}{6}-4=0\ \ \ \ |\cdot(-6)\\\\-12y+x+24=0\ \ \ \ |-24\\\\-12y+x=-24\\\\\boxed{x-12y=-24}

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3 years ago
Solve the system of equations 2x+4y+3z=6 5x+8y+6z=4
MaRussiya [10]

Answer:Solution :

{x,y,z} = {-8,52/7,-18/7}  

 

System of Linear Equations entered :

  [1]    2x + 4y + 3z = 6

  [2]    5x + 8y + 6z = 4

  [3]    4x + 5y + 2z = 0

Solve by Substitution :

// Solve equation [3] for the variable  z  

 

 [3]    2z = -4x - 5y  

 [3]    z = -2x - 5y/2  

// Plug this in for variable  z  in equation [1]

  [1]    2x + 4y + 3•(-2x-5y/2) = 6

  [1]    -4x - 7y/2 = 6

  [1]    -8x - 7y = 12

// Plug this in for variable  z  in equation [2]

  [2]    5x + 8y + 6•(-2x-5y/2) = 4

  [2]    -7x - 7y = 4

// Solve equation [2] for the variable  y  

 

 [2]    7y = -7x - 4

 [2]    y = -x - 4/7

// Plug this in for variable  y  in equation [1]

  [1]    -8x - 7•(-x -4/7) = 12

  [1]    -x = 8

// Solve equation [1] for the variable  x  

  [1]    x = - 8  

// By now we know this much :

   x = -8

   y = -x-4/7

   z = -2x-5y/2

// Use the  x  value to solve for  y  

   y = -(-8)-4/7 = 52/7  

// Use the  x  and  y  values to solve for  z  

 z = -2(-8)-(5/2)(52/7) = -18/7  

Solution :

{x,y,z} = {-8,52/7,-18/7}  

Step-by-step explanation:

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Answer:

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