Answer:
1/8
Explanation:
Father: normal vision, type A
Mother: normal vision, type A
They can only produce a colourblind son if female is the carrier for it:
XC Xc
XC XCXC XCXc
Y XCY XcY
XcY son will be colorblind. Hence father has XCY genotype and mother has XCXc genotype for vision.
They can only produce type O son if both of them are heterozygous for type A:
A O
A AA AO
O AO OO
OO son will have type O blood. Hence both father and mother have AO genotype for blood type.
Probability of having a female child=1/2
Probability of having a normal vision female child = 1 since in the first punnett square it has been shown that all female children have normal vision ( half are carriers )
Probability of having type O child = 1/4
Probability of having a female child with normal vision and type O blood = 1/2 * 1 * 1/4 = 1/8
