Consider f(x) = -4(x - 6)² + 3
This is a parabola with vertex at (6, 3).
Because the leading coefficient of -4 is negative, the curve opens downward, and the vertex is the maximum value.
Answer: Maximum of f(X) = 3
Consider the function g(x) = 2 cos(2x - π) + 4
The maximum value of the cosine function is 1.
Therefore the maximum value of g(x) is
2*1 + 4 = 6
Answer: Maximum of g(x) = 6
Answer:
2
Step-by-step explanation:
Into f (x) = x - 4, plug 5 in the place of x: 5 - 4 = 1
Into g (x) =6 - x, plug 5 in the place of x: 6 - 5 = 1
Then: 1 + 1 = 2
I believe we need two combinations. I am not sure though Thank my if this helps
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