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3 years ago

The answer for this question someone answer fast pleaseeee

Mathematics

1 answer:

nexus9112 [7]3 years ago

5 0

Answer:

???

Step-by-step explanation:

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Recommended daily intake of fiber

Ganezh [65]

25 grams per day that is the recommended daily intake of fiber

4 0

3 years ago

If you place a 26-foot ladder against the top of a 10-foot building, how many feet will the bottom of the ladder be from the bot

True [87]

Answer:

24 foot

Step-by-step explanation:

We are given that

Length of ladder=26 foot

Height of building=10 foot

We have to find the distance between the bottom of ladder and the bottom of building.

Pythagorus theorem:

$(Hypotenuse)^2=(Base)^2+(Perpendicular\;side)^2$

We have hypotenuse =AC=26 foot

Perpendicular side =AB=10 foot

Base=BC

Substitute the values in the given formula

$(26)^2=(10)^2+(BC)^2$

$676=100+(BC)^2$

$(BC)^2=676-100=576$

$BC=\sqrt{576}=24$ (Take positive because length is always positive)

BC=24 foot

Hence, the bottom of the ladder will be 24 foot from the bottom of the building.

8 0

3 years ago

Let omega be a complex number such that omega^3 = 1. Find all possible values of {1}{1 + \omega} + {1}{1 + \omega^2}. Enter all

Norma-Jean [14]

Answer:

1 is Answer.

Step-by-step explanation

$\frac{1}{1+omega^{2} } + \frac{1}{1+omega }\\$

= $\frac{(-1)*(omega + 1)}{omega^{2} }$

As we know that ω²+ω+1=0

Thus putting in above equation, we get

= $\frac{1}{(-1)*omega } + \frac{1}{(-1)*omega^{2} }$

Rearranging and simplifying:

= $\frac{-1}{omega } + \frac{-1}{omega^{2} }$

= $\frac{(-1)*(omega + 1)}{omega^{2} }$

= $\frac{(-1)*(- omega^{2} )}{omega^{2} }$

= 1 Answer

8 0

3 years ago

Henri bought a swim suit at a cost of $8. Which statements are true regarding the cost of the suit? Select three options

uysha [10]

Answer:

where are the options

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

One bar of candy A and two bars of candy B have 774 calories. Two bars of candy A and one bar of candy B contains 786 calories.

vampirchik [111]

◆ Define the variables:

Let the calorie content of Candy A = a
and the calorie content of Candy B = b

◆ Form the equations:

One bar of candy A and two bars of candy B have 774 calories. Thus:

a + 2b = 774

Two bars of candy A and one bar of candy B contains 786 calories

2a + b = 786

◆ Solve the equations:

From first equation,
a + 2b = 774
=> a = 774 - 2b

Put a in second equation
2×(774-2b) + b = 786
=> 2×774 - 2×2b + b = 786
=> 1548 - 4b + b = 786
=> -3b = 786 - 1548
=> -3b = -762
=> b = -762/(-3) = 254 calorie

◆ Find caloric content:

Caloric content of candy B = 254 calorie

Caloric content of candy A = a = 774 - 2b = 774 - 2×254 = 774 - 508 = 266 calorie

5 0

3 years ago

The answer for this question someone answer fast pleaseeee​

The answer for this question someone answer fast pleaseeee