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DanielleElmas [232]
3 years ago
5

EASY POINTS HERE FOLKS COME HELP ME OUT

Mathematics
2 answers:
expeople1 [14]3 years ago
8 0
C...........................................
Bad White [126]3 years ago
6 0
Issa kite ma dude...
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Quadrilateral JKLM is graphed with vertices at J(-2,2), K(-1,-5), L(4,0), and M(3,7).
AveGali [126]

Answer:

<u>Question (a)</u>

Midpoint of a line segment:

M=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Given:

  • J = (-2, 2)
  • L = (4, 0)

\implies \textsf{midpoint of }JL=\left(\dfrac{-2+4}{2},\dfrac{2+0}{2}\right)=(1,1)

Given:

  • M = (3, 7)
  • K = (-1, -5)

\implies \textsf{midpoint of }MK=\left(\dfrac{3-1}{2},\dfrac{7-5}{2}\right)=(1, 1)

<u>Question (b)</u>

Find slopes (gradients) of JL and MK then compare.  If the product of the slopes of JL and MK equal -1, then JL and MK are perpendicular.

\textsf{slope }m=\dfrac{y_2-y_1}{x_2-x_1}

Given:

  • J = (-2, 2)
  • L = (4, 0)

\implies \textsf{slope of }JL=\dfrac{0-2}{4+2}=-\dfrac13

Given:

  • M = (3, 7)
  • K = (-1, -5)

\implies \textsf{slope of }MK=\dfrac{-5-7}{-1-3}=3

\textsf{slope of }JL \times \textsf{slope of }MK=-\dfrac13 \times3=-1

Hence segments JL and MK are perpendicular

4 0
2 years ago
Mindy lives of a mile away from school. Ron lives as far from school as Mindy. How far is Ron's house from school?
jek_recluse [69]

Answer:

additive comparison

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Solve for x: 3 over 3x+ 1 over x+4= 10 over 7x
hram777 [196]

Answer:

3

Step-by-step explanation:

3/3x + 1/x+4 = 10/7x

3/3x + 1/x+4 = 10/7x , x=0,x=-4

1/x + 1/x+4 = 10/7x

1/x + 1/x+4 - 10/7x = 0

7(x+4)+7x-10(x+4) / 7x*(x+4) = 0

7x+28+7x-10x-40 / 7x*(x+4) = 0

4x-12 / 7x*(x+4) = 0

4x-12=0

4x-=12

x=3,x=0,x=-4

x=3

7 0
3 years ago
Find the measure of each angle.
Anton [14]

Answer:

Step-by-step explanation:

1. 51 degrees

2. 90 degrees

3. 17 degrees

4. 107 degrees

5. 121 degrees

6. 68 degrees

5 0
2 years ago
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Let y be a random variable with p(y) given in the accompanying table. find e(y ), e(1/y ), e(y 2 − 1), and v(y ). y 1 2 3 4 p(y)
Studentka2010 [4]
<span>E[Y] = 0.4·1 + 0.3·2 + 0.2·3 + 0.1·4 = 2 E[1/Y] =0.4·1/1 + 0.3·1/2 + 0.2·1/3 + 0.1·1/4 = 0.4 + 0.15 + 0.0666 + 0.025?0.64 V[Y] =E[Y2]-E[Y]2= (0.4)·12+(0.3)·22+(0.2)·32+(0.1)·42-22= 0.4+1.2+1.8+1.6-4= 5-4 = 1</span>
8 0
3 years ago
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