Show that if p(a) ⊂ p(b) then a ⊂ b.
<span>I will assume p() means power set. </span>
<span>proof: let x∈a, then {x} ∈ p(a) and so by hypothesis {x} ∈ p(b). However {x} could not be in p(b) unless x∈b. This shows that each element of a is an element of b and hence a ⊂ b.
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Answer: $998.67
Step-by-step explanation:
M = P[r(1+r)^n/((1+r)^n)-1)]
This does not include taxes, insurance, or PMI
Amount of oil sandi has = 2 1/3 * 12
= 7/3 * 12 = 7*4 = 28 quarts
Answer:
the roots are {-4/3, 4/3}
Step-by-step explanation:
Begin the solution of 11=6|-2z| -5 by adding 5 to both sides:
11=6|-2z| -5 becomes 16 = 6|-2z|.
Dividing both sides by 12 yields
16/12 = |-z|
There are two cases here: first, that one in which z is positive and second the one in which z is negative.
If z is positive, 4/3 = -z, and so z = -4/3, and:
If z is negative, 4/3 = z
Thus the roots are {-4/3, 4/3}
