Answer:
My own answer to your question is x=10
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
Answer:
The last one
Step-by-step explanation:
There are going to be two solutions because the "biggest" x is x^2 but you can factor to find what they actually are.
It is an 8/15 probability. there are 15 marbles total (5y+7p+3pl=15)
5/15y, 7/15p, 3/15.
5/15+3/15= 8/15