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soldi70 [24.7K]
2 years ago
10

X+5y; use x = 1 5/6, and y = 3 1/6

Mathematics
1 answer:
Phantasy [73]2 years ago
3 0

Answer:

53/3

Step-by-step explanation:

1 5/6=11/6

3 1/6=19/6

---------------

11/6+5(19/6)=11/6+95/6=106/6

simplify

53/3

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A cylindrical can has a volume of 2in^(3). Express the surface area of the can as a function of its radius,r.
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7 0
3 years ago
I WILL GIVE BRAILIEST PLEASE HELP
Mila [183]

Answer:

$3.49 for the muffin, and $2.96 for the coffee

Step-by-step explanation:

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(2.75)(1.075) = 2.96

How to find the factor to multiply by

1.075 = 1+.075, 7.5% = 7.5/100 =  .075

3 0
2 years ago
Read 2 more answers
The national vaccine information center estimates that 90% of americans have had chickenpox by the time they reach adulthood.50
timama [110]
Given:
 p = 90% = 0.9, the probability that an adult has had chickenpox by age 50.
Therefore,
q = 1 - p = 0.1, the probability that an adult has not had chickenpox by age 50.

Part (a)
Because there are only two answers: "Yes" or "No" to whether an adult has had chickenpox by age 50, the use of the binomial distribution is justified.

Part (b):
Calculate the probability that exactly 97 out of 100 sampled adults have had chickenpox.
The probability is
P₁ = ₁₀₀C₉₇ (0.9)⁹⁷ (0.1)³ = 0.0059

Answer: 0.006 or 0.6%

Part (c)
Calculate the probability that exactly 3 adults have not had chickenpox.
Theis probability is equal to 
P₂ = 1 - P₁ = 1 - 0.006 = 0.994

Answer: 0.994 or 99.4%

Part (d)
Calculate the probability that at least 1 out of 10 randomly selected adults have had chickenpox.
The probability is
P₃ = ₁₀C₀ (0.9)⁰ (0.1)¹⁰ + ₁₀C₁ (0.9)¹ (0.1)⁹ = 10⁻¹⁰ + 10⁻⁹ = 10⁻⁹ ≈ 0

Answer: 0

Part (e)
Calculate the probability that at most 3 out of 10 randomly selected adults have not had chickenpox.
The probability is
P₄ = 1 - [₁₀C₀ (0.9)⁰(0.1)¹⁰ + ₁₀C₁ (0.9)¹(0.1)⁹ + ₁₀C₂ (0.9)²(0.1)⁸ + ₁₀C₃ (0.9)³(0.1)⁷]
     = 1 - (10⁻¹⁰ + 9 x 10⁻⁹ + 3.645 x 10⁻⁷ + 8.748 x 10⁻⁶)
     = 1

Answer:  1.0 or 100%

5 0
3 years ago
Read 2 more answers
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