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DENIUS [597]
3 years ago
9

Dice A has the sides 2, 2, 4, 4, 6, 6 and Dice B has 1, 3, 1, 3, 1, 3. What is the probability that when you roll the dice Dice

A - Dice B is equal to 1?
Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
6 0

Answer:

i remember doing a question just like this. Im pretty sure the answer is 1/4

Step-by-step explanation:

xxMikexx [17]3 years ago
4 0

Answer:

  • 1/3 or 33.33%

Step-by-step explanation:

<u>Dice A - Dice B = 1 is likely if:</u>

  • 1. Dice A = 2 and Dice B = 1

or

  • 2. Dice A = 4 and Dice B = 3

<u>Probability of the first scenario is:</u>

  • 2/6*3/6 = 1/6

<u>Probability of the second scenario is:</u>

  • 2/6*3/6 = 1/6

<u>Total is:</u>

  • 1/6 + 1/6 = 2/6 = 1/3 or 33.33%
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SpyIntel [72]

Answer:

|4.2 - 6.8|  + (2.4 + 7.2)

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WILL MARK BRAINLIEST, JUST HELP ME PLS
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Answer:

SAS theorem

Step-by-step explanation:

If \frac{CE}{CB} = \frac{DC}{AC} and m∠ECD = m∠BCA, then the triangles are similar by the SAS theorem.

\frac{EC}{BC} =  \frac{14}{21} = \frac{2}{3}           \frac{DC}{AC} = \frac{18}{27} = \frac{2}{3}

So,  \frac{CE}{CB} = \frac{DC}{AC}  and m∠ECD = m∠BCA because vertical angles are congruent

Therefore ΔECD is similar to ΔBCA by SAS theorem

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3 years ago
Find two numbers that have a sum of -2 and a product of -48 (please show work if possible)​
andreev551 [17]

Answer: -8 and 6

Step-by-step explanation:

factors of 48: 1,2,4,6,8,12,24,48

1 x 48

2 x 24

4 x 12

6 x 8

for a negative product, one of the factors must be negative and the other positive.

for two number to have a sum of -2, the greater number must be the negative number, and both numbers should have be two values apart (ex. 6 and 8, 3 and 5, 12 and 14, etc.). In this case, 8 would have to be negative whereas 6 will be left positive.

and then we check:

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Vikentia [17]

\text{If is}\\\\\left\{\begin{array}{ccc}0.2-0.3y=4\\2.3x-y=1.2\end{array}

Answer:

\large\boxed{\left(-\dfrac{344}{69},\ -\dfrac{38}{3}\right)}

Step-by-step explanation:

\left\{\begin{array}{ccc}0.2-0.3y=4\\2.3x-y=1.2&\text{multiply both sides by (-0.3)}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}0.2-0.3y=4\\-0.69x+0.3y=-0.36\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad-0.69x+0.2=3.64\qquad\text{subtract 0.2 from both sides}\\.\qquad-0.69x=3.44\qquad\text{divide both sides by (-0.69)}\\.\qquad x=-\dfrac{3.44\cdot100}{0.69\cdot100}\\.\qquad \boxed{x=-\dfrac{344}{69}}\\\\\text{Calculate the value of y from first equation:}

0.2-0.3y=4\qquad\text{subtract 0.2 from both sides}\\-0.3y=3.8\qquad\text{divide both sides by (-0.3)}\\y=-\dfrac{3.8\cdot10}{0.3\cdot10}\\\boxed{y=-\dfrac{38}{3}}

--------------------------------------------------------------------------

\text{If is}\\\\\left\{\begin{array}{ccc}0,2x-0,3y=4\\2.3x-y=1.2\end{array}\right

Answer:

\large\boxed{\left(-\dfrac{52}{7},\ -\dfrac{128}{7}\right)}

Step-by-step explanation:

\left\{\begin{array}{ccc}0.2x-0.3y=4&\text{multiply both sides by 10}\\2.3x-y=1.2&\text{multiply both sides by 10}\end{array}\right\\\\\left\{\begin{array}{ccc}2x-3y=40&\text{multiply both sides by (-10)}\\23x-10y=12&\text{multiply both sides by 3}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-20x+30y=-400\\69x-30y=36\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad49x=-364\qquad\text{divide both sides by 49}\\x=-\dfrac{364:7}{49:7}\\.\qquad\boxed{x=-\dfrac{52}{7}}

2\left(-\dfrac{52}{7}\right)-3y=40\\-\dfrac{104}{7}-3y=40\qquad\text{multiply both sides by 7}\\-104-21y=280\qquad\text{add 104 to both sides}\\-21y=384\qquad\text{divide both sides by (-21)}\\y=-\dfrac{384:3}{21:3}\\\boxed{y=-\dfrac{128}{7}}

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4 years ago
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