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DENIUS [597]
3 years ago
9

Dice A has the sides 2, 2, 4, 4, 6, 6 and Dice B has 1, 3, 1, 3, 1, 3. What is the probability that when you roll the dice Dice

A - Dice B is equal to 1?
Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
6 0

Answer:

i remember doing a question just like this. Im pretty sure the answer is 1/4

Step-by-step explanation:

xxMikexx [17]3 years ago
4 0

Answer:

  • 1/3 or 33.33%

Step-by-step explanation:

<u>Dice A - Dice B = 1 is likely if:</u>

  • 1. Dice A = 2 and Dice B = 1

or

  • 2. Dice A = 4 and Dice B = 3

<u>Probability of the first scenario is:</u>

  • 2/6*3/6 = 1/6

<u>Probability of the second scenario is:</u>

  • 2/6*3/6 = 1/6

<u>Total is:</u>

  • 1/6 + 1/6 = 2/6 = 1/3 or 33.33%
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Lily has $2. 75 in her pocket, consisting of dimes and quarters. If there are 17 coins in all, how many of each does she have?.
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Answer:

Lily has 7 Quarters and 10 Dimes

Step-by-step explanation:

Let's use pennies instead of $.

Let <u>D</u> and <u>Q</u> stand for the numbers of Dimes and Quarters, respectively.

We are told that there are 17 coins total:

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We also learn that they amount to 275 (pennies).  We can write that as:

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We have two equations and two unknowns.  We can rearrange one equation to find the value of either of the unknowns, and then use that it the second equation.

I'll rearrange the first:  

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<u>   D = 17 - Q</u>

Now use this value of D in the second equation:

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<u>Q = 7  :  7 Quarters.</u>

<u></u>

Since D + Q = 17:

D + 7 = 17

<u>D = 10 Dimes</u>

==========================================

Let's check these results:

Q = 7 Quarters

D = 10 Dimes

1.  Is this 17 coins in total?  (7+10 = 17)  <u>YES</u>

2.  Does this add to $2.75?  (10*10) + (7*25) = 275 cents?

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============================

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