We have to find the expected value for the PlayBall lottery.
The price of the ticket = $1
Prize amount = $250
If a player wins, he will be winning $249 as the price is not paid back along with the prize amount. He is spending $1, getting back $250, so the net amount he is getting back is $249.
Now we have to find the probability of winning and losing.
Number of letters from A to T = 20
Number of digits from 0 to 9 = 10
Probability of picking up the same letter that was picked on that day = 1/20
Probability of picking up the same number that was picked on that day = 1/10
Thus, the Probability of picking up the same letter and same number that was picked on that day =

Thus, the probability of winning = 1/200
The probability of losing =

The expected value E for the PlayBall lottery will be:
Thus, the option C gives the correct answer
Answer:
(0, 2)
Step-by-step explanation:
1. Plot the pionts on a graph
2.You can see the possible turning point is (0, 2). It changes from decreasing to increasing.
When we have exponents like such (x^-6)^-2 , the numbers are multiplying, so we have x^12, then we take that value and, because it is dividing with the same base, we substract the numbers, so x^12-(-4) = x^16.
Answer:
Let x = the measure of the smaller angle
Let 3x + 40 = the measure of the larger angle
x + 3x + 40 = 180
4x = 140
x = 35º
3x + 40 = 3(35) + 40 = 145º
Step-by-step explanation: