your answer would be A. 122/27
Answer:
The function which represents this sequence will be:
Hence, option (A) is true.
Step-by-step explanation:
Given the sequence
An arithmetic sequence has a constant difference 'd' and is defined by
computing the differences of all the adjacent terms
As the difference is the same, so
as
Thus, substituting , in the nth term of an arithmetic sequence
Therefore, the function which represents this sequence will be:
Hence, option (A) is true.
Answer:
B hope it helps
Step-by-step explanation:
(a) The lateral surface area of the prism is 720 sq units and the total surface area is 752 sq units.
(b) The lateral surface area of the cone is 136π sq units and the total surface area is 200π sq units.
(c) The lateral surface area of the cylinder is 242π sq units and the total surface area is 484π sq units.
<h3>
Lateral surface area of the prism</h3>
L.S.A = Ph
where;
- P is perimeter of the base
- h is height of the prism
h² = 17² - 8²
h² = 225
h = 15
L.S.A = (3 x 16) x 15 = 720 sq units
<h3>Total s
urface area of the prism</h3>
T.S.A = PH + 2B
T.S.A = 720 + 2(16) = 752 sq units
<h3>
Lateral surface area of the cone</h3>
L.S.A = πrt
where;
- t is the slant height = 17
r² = 17² - 15²
r² = 64
r = 8
L.S.A = π(8)(17) = 136π sq units
<h3>
Total surface area of the cone</h3>
T.S.A = πrt + πr²
T.S.A = 136π sq units + π(8)²
T.S.A = 200π sq units
<h3>
Lateral surface area of the cylinder</h3>
L.S.A = 2πrh
where;
- r is the radius of the cylinder = 11
- h is height of the cylinder = 11
L.S.A = 2π(11 x 11) = 242π sq units
<h3>Total
surface area of the cylinder</h3>
T.S.A = 2πrh + 2πr² = 2πr(r + h)
T.S.A = 2π(11)(11 + 11)
T.S.A = 484π sq units.
Thus, the lateral surface area of the prism is 720 sq units and the total surface area is 752 sq units.
- the lateral surface area of the cone is 136π sq units and the total surface area is 200π sq units.
- the lateral surface area of the cylinder is 242π sq units and the total surface area is 484π sq units.
Learn more about surface area here: brainly.com/question/76387
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