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4 years ago

Why light refracted?

Physics

2 answers:

Hunter-Best [27]4 years ago

4 0

because of the reflection. if this isnt correct pls let me know :)

Kisachek [45]4 years ago

4 0

Light refracts or "bends" when it passes through the boundary of two NOT similar materials because the speed and wavelength of light changes. Light does not refract or "bend" when crossing between two medias of identical refractive indices, or when it falls perpendicular to the interface.....

Hope i helped! :)

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How large is the Milky Way Galaxy? A. It is the largest galaxy ever observed. B. It takes up over half of the known universe. C.

lisabon 2012 [21]

Answer:

D. It is very small when compared to the universe

Explanation:

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3 years ago

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dezoksy [38]

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3 years ago

Read 2 more answers

A plastic rod 1.3 m long is rubbed all over with wool, and acquires a charge of -3e-08 coulombs. we choose the center of the rod

Anestetic [448]

(a) The plastic rod has a length of L=1.3m. If we divide by 8, we get the length of each piece:
$L/8=1.3m/8=0.1625 m$

(b) The center of the rod is located at x=0. This means we have 4 pieces of the rod on the negative side of x-axis, and 4 pieces on the positive side. So, starting from x=0 and going towards positive direction, we have: piece 5, piece 6, piece 7 and piece 8. Each piece is 0.1625 m long. Therefore, the center of piece 5 is at 0.1625m/2=0.0812 m. And the center of piece 6 will be shifted by 0.1625m with respect to this:
$c_6 = 0.0812m+0.1625m=0.2437 m$

(c) The total charge is $Q=-3 \cdot 10^{-8}C$ . To get the charge on each piece, we should divide this value by 8, the number of pieces:
$Q/8=-3\cdot 10^{-8}C/8=-3.75\cdot 10^{-9}C$

(d) We have to calculate the electric field at x=0.7 generated by piece 6. The charge on piece 6 is the value calculated at point (c):
$q= -3.75\cdot 10^{-9}C$
If we approximate piece 6 as a single charge, the electric field is given by
$E=k_e \frac{q}{d^2}$
where $k_e=8.99\cdot 10^9Nm^2C^{-2}$ and d is the distance between the charge (center of piece 6, located at 0.2437m) and point a (located at x=0.7m). Therefore we have
$E= 8.99\cdot 10^9 Nm^2C^{-2} \frac{-3.75\cdot 10^9 C}{(0.2437m-0.7m)^2} =-161.9 V/m$
poiting towards the center of piece 6, since the charge is negative.

(e) missing details on this question.

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3 years ago

Theorem: there is no smallest positive rational number.theorem: there is no smallest positive rational number. a proof by contra

matrenka [14]

Assume there is a smallest rational integer that has the following form: a/b

Then observe that we can define a/(b+1), which is strictly less than a/b because its divisor is bigger and is rational because it is the product of two numbers. Due to the contradiction created by our original claims that a/b is the smallest rational number that is possible, we might conclude that there is no such thing as the smallest rational number.

There can therefore be no smallest rational number because we may always define a smaller rational number than the one we now possess.

<h3>What is Rational number ?</h3>

Any number that can be expressed as a ratio is considered reasonable. It is therefore possible to represent it as a fraction when the numerator and denominator are both full numbers.

Learn more about Rational number here:

brainly.com/question/12088221

#SPJ4

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2 years ago

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rusak2 [61]

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3 years ago

Why light refracted?​

Why light refracted?