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3 years ago

Which one of the following statements indicates the result of Kepler's astronomical calculations?

1 answer:

5 0

The correct answer for the question that is being presented above is this one: "<span>c. Planets orbit in elliptical patterns; a planet's orbit covers equal areas in equal amounts of time; planets' orbits are shorter or longer depending on their distance from the Sun."</span>

Here are the following choices:
a. Planets orbit in elliptical patterns; the bigger the planet, the more gravitational pull; a planet's gravitational pull is stronger or weaker depending on its distance from the Sun.

b. A planet's orbit covers equal distances in equal amounts of time; the speed of a planet's orbit depends on its distance from the Sun; the bigger the planet, the slower it moves.

c. Planets orbit in elliptical patterns; a planet's orbit covers equal areas in equal amounts of time; planets' orbits are shorter or longer depending on their distance from the Sun.

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A +35 µC point charge is placed 46 cm from an identical +35 µC charge. How much work would be required to move a +0.50 µC test c

Ira Lisetskai [31]

Answer:

512.5 mJ

Explanation:

Let the two identical charges be q = +35 µC and distance between them be r₁ = 46 cm. A charge q' = +0.50 µC located mid-point between them is at r₂ = 46 cm/2 = 23 cm = 0.23 m.

The electric potential at this point due to the two charges q is thus

V = kq/r₂ + kq/r₂

= 2kq/r₂

= 2 × 9 × 10⁹ Nm²/C² × 35 × 10⁻⁶ C/0.23 m

= 630/0.23 × 10³ V

= 2739.13 × 10³ V

= 2.739 MV

When the charge q' is moved 12 cm closer to either of the two charges, its distance from each charge is now r₃ = r₂ + 12 cm = 23 cm + 12 = 35 cm = 0.35 m and r₄ = r₂ - 12 cm = 23 cm - 12 cm = 11 cm = 0.11 cm.

So, the new electric potential at this point is

V' = kq/r₃ + kq/r₄

= kq(1/r₃ + 1/r₄)

= 9 × 10⁹ Nm²/C² × 35 × 10⁻⁶ C(1/0.35 m + 1/0.11 m)

= 315 × 10³(2.857 + 9.091) V

= 315 × 10³ (11.948) V

= 3763.62 × 10³ V

= 3.764 MV

Now, the work done in moving the charge q' to the point 12 cm from either charge is

W = q'(V' - V)

= 0.5 × 10⁻⁶ C(3.764 MV - 2.739 MV)

= 0.5 × 10⁻⁶ C(1.025 × 10⁶) V

= 0.5125 J

= 512.5 mJ

8 0

3 years ago

An electric car has a battery that can hold 16 kwh of energy. if the battery is designed to operate at 340 v, how many coulombs

Zanzabum

charge needed= 169412 C

Explanation:

energy stored in the battery= 16 KWh= 16 (1000 W)(3600 s)= 5.76 x 10⁷ J

Energy stored is given by U= q V

q= charge

V= voltage= 340 V

so 5.76 x 10⁷ = q (340)

q= 169412 C

4 0

4 years ago

A rock falls from a vertical cliff that is 4.0 m tall and experiences no significant air resistance as it falls. At what speed w

Zinaida [17]

Answer:

v = 6.3 m/s

Explanation:

Since no significant air resistance exists, total mechanical energy must be kept constant at any time.
At the top of the cliff, all the energy is gravitational potential energy, as follows:

$E_{i} = K_{i} + U_{i} = 0 + U_{i} (1)$

If we choose the ground level as our zero reference level for the gravitational potential energy, Ui is simply:
Ui = m*g*h (1)
At any height, the sum of the kinetic and the gravitational potential energy must be equal to (1).
We know from the question, that at the point of interest, both types of energies must be equal each other, so we can write the following expression from (1):

$m*g* h = 2*\frac{1}{2}*m*v^{2} (2)$

Dividing both sides by m, simplifying, and solving for v, we get:

$v = \sqrt{g*h} =\sqrt{9.8m/s2*4.0m} = 6.26 m/s (3)$

v = 6.3 m/s (with two significative figures)

8 0

3 years ago

If a 50-kg Person is running at a rate of 2m/s, the person's momentum is _____ kg• m/s.

sergiy2304 [10]

Answer:

100

Explanation:

Use equation p=mv

p=(50kg)(2m/s)= 100

8 0

3 years ago

PLEASE HURRY I HAVE 10 MINUTES LEFT ON MY TOPIC TEST

Mazyrski [523]

The answer is D.

Velocity is the speed in a particular direction.

Saying that you are going from Los Angeles to Catalina Island is not a particular direction, it is an end destination.

3 0

3 years ago