Let's use our largest amount (quarter) to see how many can fit evenly into 1.74.
- 1.74/0.25 = 6.96
- The most quarters that can fit into $1.74 is 6.
---Multiply $0.25 by 6 = $1.50
---Subtract $1.50 from $1.74 = $0.24
---We need to use the rest of the coins to fill up $0.24.
Now let's use our second largest amount (dime) to see how many can fit evenly into 0.24.
- 0.24/0.10 = 2.4
- The most dimes that can fit into $0.24 is 2.
---Multiply $0.10 by 2 = $0.20
---Subtract $0.20 from $0.24 = $0.04
No nickels can fit into $0.04, because they are worth $0.05.
We can use our least amount (pennies) to fill in the $0.04 remaining.
Your answer is 6 quarters, 2 dimes, and 4 pennies.
Answer:
(10, - 9 )
Step-by-step explanation:
Given the 2 equations
y = - 2x + 11 → (1)
y = - 3x + 21 → (2)
Substitute y = - 2x + 11 into (2)
- 2x + 11 = - 3x + 21 ( add 3x to both sides )
x + 11 = 21 ( subtract 11 from both sides )
x = 10
Substitute x = 10 into either of the 2 equations and evaluate fir y
Substituting into (1)
y = - 2(10) + 11 = - 20 + 11 = - 9
solution is (10, - 9 )
5.21 would just be 5 or 5.2 depending on what place you need to round.
Answer:
16 mls of the 75% solution and 20 mls of the 0.57% solution.
Step-by-step explanation:
Set up a system of equations:
Let x = volume of 75% solution and y be volume of 57% solution
0.75x + 0.57y = 36*0.65
0.75x + 0.57y = 23.4.......(1)
x + y = 36.........(2)
From equation (2):
y = 36 - x
Substituting this into equation(1):
0.75x + (0.57(36 - x) = 23.4
0.75x + 20.52 - 0.57x = 23.4
0.18x = 23.40 - 20.52 = 2.88
x = 2.88/0.18
x = 16
so from equation (2): y = 36-16 = 20.
There are 12 tickets needed. Just add all the 4's together.
