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3 years ago

Find the slope of the line containing the two points. (2,5),(-3,-2) Please show work

Mathematics

1 answer:

HACTEHA [7]3 years ago

8 0

Answer:

7/5

Step-by-step explanation:

To solve this problem we will use the formula to find the slope of a line given two points (x₁, y₁), (x₂, y₂)

The formula is:

$m= \frac{y{_2} -y_{1}}{x_{2}-x_{1} } \\\\$

So, we're going to use the points (2,5), (-3, -2) in this formula.

$m= \frac{-2-(5)}{-3-(2)} \\m=\frac{-2-5}{-3-2}\\m=\frac{-7}{-5} \\m=\frac{7}{5}$

Therefore, the slope is 7/5

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PLEASE HELP ME WITH THIS THANKS

kotykmax [81]

Answer:

SA = 1244.64 square centimeters

Step-by-step explanation:

From the attached figure

The formula of the surface area of the prism is SA = 2B + PH, where

B is the area of its base
P is the perimeter of its base
H is the distance between its bases

The base of the prism is a regular hexagon with side 8 cm

If you join each vertex of the hexagon with its center you will form 6 congruent triangles with base 8 cm and height 6.93 cm

The area of the hexagon = 6 × area of a triangle

∵ The base of the triangle = 8 cm

∵ Its height = 6.93 cm

- The formula of the area of a triangle is A = $\frac{1}{2}$ × base × height

∴ Area of the triangle = $\frac{1}{2}$ × 8 × 6.93 = 27.72 cm²

- Lets find the area of the hexagon

∴ The area of the hexagon = 6 × 27 .72 = 166.32 cm²

∴ B = 166.32 cm²

The formula of the perimeter of the regular hexagon is P = 6 × s, where s is the length of its side

∵ The side of the hexagon is 8 cm

∴ P = 6 × 8

∴ P = 48 cm

∵ The distance between the two bases is 19 cm

∴ H = 19 cm

Substitute the values of B, P and H in the formula of the surface area above

∵ SA = 2(166.32) + (48)(19)

∴ SA = 332.64 + 912

∴ SA = 1244.64 square centimeters

7 0

2 years ago

Allen runs at an average rate of 9 mi/hr and walks at a average rate of 3 mi/hr. Write an equation in standard form to relate th

den301095 [7]

Answer:

The equation would be $30=12+9x$ .

Allen will Run for 2 hours.

Step-by-step explanation:

Given:

Total Distance traveled = 30 miles

Average rate of walking = 3 mi/hr

Average rate of running = 9 mi/hr

Time for walking = 4 hours

W need to find the time for running.

Solution:

Let Number of hrs required for running be 'x'.

Total Distance traveled is equal Distance Traveled in walking plus Distance traveled in Running

But Distance is equal Rate multiplied by Time.

Framing in equation form we get;

Hence Total Distance Traveled = Rate of walking × Hours of walking + Rate of Running × Hours of running.

Substituting the values we get;

$30 = 3\times4 +9x\\\\30=12+9x$

Hence The equation would be $30=12+9x$

Solving above equation we get;

$9x=30-12\\\\9x=18\\\\x=\frac{18}{9}=2\ hrs$

Hence Allen will Run for 2 hours.

8 0

3 years ago

Bored so question? Fav Bruno Mars song, Fav Meg the stallion song, Fav Michael Jackson song, Fav Arianna Grande song? You don't

icang [17]

Answer:

Versace on the Floor. Captain Hook. Rock with You. Break up with Your Girlfriend.

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Find the nth degree polynomial function with real coefficients satisfying the given conditions.

RUDIKE [14]

$\bf (x+1)(x-3)(x-2-4i)(x-2+4i)
\\\\
\textit{now, let's take a peek at }(x-2-4i)(x-2+4i)\\
\textit{and recall our }\textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-----------------------------\\\\
(x-2-4i)(x-2+4i)\implies [(x-2)-(4i)][(x-2)+(4i)]
\\\\\
[(x-2)^2-(4i)^2]\implies [(x^2-2x+4)-(4^2\boxed{i^2})]
\\\\\
[(x^2-2x+4)-(16\cdot \boxed{-1})]\implies [(x^2-2x+4)+16]
\\\\
(x^2-2x+20)\\\\
-----------------------------$

$\bf thus
\\\\

\begin{array}{llll}
(x+1)(x-3)\\(x-2-4i)(x-2+4i)
\end{array}\implies (x+1)(x-3)(x^2-2x+20)
\\\\\\
(x^2-2x-3)(x^2-2x+20)\implies 
\begin{array}{llll}
x^4-2x^3+20x^2-2x^3\\+4x^2-40x+3x^2-6x+60
\end{array}
\\\\\\
x^4-4x^3+27x^2-46x+60$

4 0

2 years ago

Part A is asking how long the bridge is and Part B is asking how expensive it would be if each foot it 1500

katrin [286]

Answer:

(a)80 feet

(b)$120,000

Step-by-step explanation:

Part A

Intersecting Secant-Tangent Theorem

If a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.

In the attached diagram, the theorem applied is:

$|AX|^2=|UX|*|TX|$

Comparing with our diagram:

|AX|=30 feet

|UX|=10 feet

Length of the Bridge,L

Therefore:

$30^2=10 X ($Length of the Bridge+10)$

900=10(L+10)

L+10=900/10

L+10=90

L=90-10=80 feet

Length of the Bridge=80 feet

Part B

If each foot costs $1500

Cost of the bridge=$1500*80=$120,000

4 0

2 years ago