Answer:
Using Math.
Step-by-step explanation:
You solve it using math.
See, you should have been more specific with your question, maybe said "What is the answer" not "How do I solve".
But I guess I'll help you out bro
<em>Multiply</em> both sides by 6
that gives you -x>18
then <em>multiply</em> both sides by -1
which means you gotta <u>flip the sign</u>
so final answer is x<-18
These would be 2 of the 4 equations, because 6 times 9 equals 54 and 9 times 6 equals 54, but are written in a different way. Thus meaning they are 2 of the 4 equations.
These 2 would be the final to, because 54 divided by 6 is 9, and 54 divided by 9 is 6. Thus meaning they are the final 2 equations.
I hope this helps!
By=x+2, as this is the only equation that shows the relation between 2 variables
Answer:
30
Step-by-step explanation:
3 x 2 x 5 equals 30
Answer:

Step-by-step explanation:
<u>Properties of Logarithms</u>
We'll recall below the basic properties of logarithms:

Logarithm of the base:

Product rule:

Division rule:

Power rule:

Change of base:

Simplifying logarithms often requires the application of one or more of the above properties.
Simplify

Factoring
.

Applying the power rule:

Since


Applying the power rule:

Applying the logarithm of the base:
