A force of 34N stretches a very light ideal spring 0.73 m from equilibrium, What is the force constant (spring constant) of the
1 answer:
Answer:
Spring constant, k = 47 N/m
Explanation:
It is given that,
Force applied to a spring, F = 34 N
A very light ideal spring moves 0.73 m from equilibrium position i.e. x = 0.73 m
We have to find the force constant or spring constant of the spring. It can be calculated using Hooke's law. According to him, the force acting on the spring when it compresses or stretches is given by :
(-ve sign shows opposite direction)
k = 46.5 N/m
or
k = 47 N/m
Hence, the spring constant of the spring is 47 N/m.
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Answer:
The angular separation between the refracted red and refracted blue beams while they are in the glass is 42.555 - 42.283 = 0.272 degrees.
Explanation:
Given that,
The respective indices of refraction for the blue light and the red light are 1.4636 and 1.4561.
A ray of light consisting of blue light (wavelength 480 nm) and red light (wavelength 670 nm) is incident on a thick piece of glass at 80 degrees.
We need to find the angular separation between the refracted red and refracted blue beams while they are in the glass.
Using Snell's law for red light as :
Again using Snell's law for blue light as :
The angular separation between the refracted red and refracted blue beams while they are in the glass is 42.555 - 42.283 = 0.272 degrees.