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Flauer [41]
3 years ago
11

Two infinite planes of charge lie parallel to each other and to the yz plane. One is at x--1 m and has a surface charge density

of σ =-2.0 pC/m2. The other is at x = 5 m and has a surface charge density of σ 5.8 με/m2. Find the electric field for the following locations. a)x-1 m N/C (b)-1m
Physics
1 answer:
MariettaO [177]3 years ago
5 0

Answer:

    Ea = 3.2 10⁵ N / C

Explanation:

To calculate the electric field of each plane we will use Gauss's law, we create a Gaussian surface that is a cylinder that has the axis perpendicular to the plane, in this case the flow line between the cylinder walls and the surface is zero and all the flow is perpendicular to the base of the cylinder.

We apply the law of gauss flow to each side is the value of the electric field (E) for the area of ​​the cylinder (A); whereby the flow in the two directions is 2 E A

                 Φ = 2E A = ρₙt / εo

Where ρₙ is the charge inside the cylinder, as the charge density gives us, σ = Q / A

                 ρₙ = σ A

     By which we can clear the electric field

                E = σ A / 2εo

where it is worth 8.85 10⁻¹² C² / N² m². Let's calculate with this equation in the field for each plane

1  plane    σ= -2.0 pC / m²

               E1 = -2. 10⁻¹² / 2 8.85 10⁻¹²

               E1 = -0.113 N / C

The field line is directed to the plane

2 Plane    σ = 5.8 mC / m2

             

               E2 = 5.8 10-6 / 2 8.85 10-12

               E2 = 3,277 10 5 N / A

Field lines leave the plane

As we have the values ​​of each field in the whole space. Let's calculate in the field at the point x = 1 m

   To do this we must add the fields at the selected point vectorally, for this distance the point is between the two planes, so the field of plane 1 points to the left and the point of plane 2 also points to the left, consequently field adds

               Ea = E1 + E2

               Ea = 0.113 + 3.277 10⁵

               Ea = 3.2 10⁵ N / C

At point X = -1 m in this case the point is on plane 1, so this plane does not generate any field, it is an equipotential surface, the total field is equal to field 2

              Ea = E1 = 3.2 10⁵ N / C

Note that there is no difference in numbers values ​​by the difference between the load between each plane

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Answer:

<em>The end of the ramp is 38.416 m high</em>

Explanation:

<u>Horizontal Motion </u>

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The maximum horizontal distance traveled by the object can be calculated as follows:

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If the maximum horizontal distance is known, we can solve the above equation for h:

\displaystyle h=\frac  {d^2g}{2v^2}

The skier initiates the horizontal motion at v=25 m/s and lands at a distance d=70 m from the base of the ramp. The height is now calculated:

\displaystyle h=\frac  {70^2\cdot 9.8}{2\cdot 25^2}

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h= 38.416 m

The end of the ramp is 38.416 m high

8 0
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HELP PLEASE!! GIVING BRAINLIEST!! If you answer this correctly ill answer some of your questions you have posted! (20pts)
anyanavicka [17]

Explanation:

potential energy =360800J

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A grating whose slits are 3.2x10^-4 cm apart produces a third-order fringe at a 25.°0 angle. What is the wavelength of light tha
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Answer:

The light used has a wavelenght of 4.51×10^-7 m.

Explanation:

let:

n be the order fringe

Ф be the angle that the light makes

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λ be the wavelength of the light

then, by Bragg's law:

n×λ = d×sin(Ф)

λ = d×sin(Ф)/n

λ = (3.2×10^-4 cm)×sin(25.0°)/3

  = 4.51×10^-5 cm

  ≈ 4.51×10^-7 m

Therefore, the light used has a wavelenght of 4.51×10^-7 m.

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A physicist is investigating a beam of laser light of wavelength 550 nm. The light strikes a target that is 189 meters away from
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Explanation:

I hope this helps☺️

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Indica qué es una propiedad específica de la materia. Además explica por qué son útiles las propiedades específicas de la materi
Katyanochek1 [597]

Answer:

Check Explanation

Comprobar explicación

Explanation:

English Translation

Indicate what a specific property of matter is. Also explain why the specific properties of matter are useful compared to the general ones.

Solution

The specific properties of matter are properties that describes the intensive properties of the system. They are properties that do not depend on or change with the extent or size of the system. They are usually obtained by dividing the generalised properties or extensive properties by the extent or size of matter to make them independent of size/extent/Mass.

Examples of specific properties include specific heat capacity, specific volume etc. They usually have units of general units/Mass units.

The specific properties of matter are more important than the general ones because

- They help in general comparisons of the properties of different materials. They are used to rank, classify and compare properties of different materials.

- They are used in reference table/data to easily record easily accessible properties of matter. It helps to record standards that are general and independent of sizes/extents/Mass, thereby keeping the reference table/data/chart precise and concise.

- They provide us with values that are easy to memorize and remember, unlike trying to cram the different properties of different masses/sizes of matter.

In Spanish/En español

Las propiedades específicas de la materia son propiedades que describen las propiedades intensivas del sistema. Son propiedades que no dependen ni cambian con la extensión o el tamaño del sistema. Por lo general, se obtienen dividiendo las propiedades generalizadas o las propiedades extensivas por la extensión o el tamaño de la materia para hacerlas independientes del tamaño / extensión / masa.

Los ejemplos de propiedades específicas incluyen capacidad calorífica específica, volumen específico, etc. Usualmente tienen unidades de unidades generales / unidades de masa.

Las propiedades específicas de la materia son más importantes que las generales porque

- Ayudan en las comparaciones generales de las propiedades de diferentes materiales. Se utilizan para clasificar, clasificar y comparar propiedades de diferentes materiales.

- Se utilizan en la tabla / datos de referencia para registrar fácilmente propiedades de materia fácilmente accesibles. Ayuda a registrar estándares que son generales e independientes de tamaños / extensiones / masa, manteniendo así la tabla / datos / tabla de referencia precisa y concisa.

- Nos proporcionan valores que son fáciles de memorizar y recordar, a diferencia de tratar de agrupar las diferentes propiedades de diferentes masas / tamaños de materia.

Hope this Helps!!!

¡¡¡Espero que esto ayude!!!

7 0
2 years ago
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