What is the precision (relative error) of the centripetal force divided by the mass if the velocity and the radius are each dete
1 answer:
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(a) The impulse delivered to the ball by the racket is 5.24 kg.m/s
(b) The work that the racket does on the ball is -35.1 Joule
<h3>Further Explanation</h3><u>Given :</u>
mass of ball = m = 0.06 kg
initial velocity = v₁ = -50.4 m/s
final velocity = v₂ = 37.0 m/s
<u>Unknown :</u>
(a) Impulse = I = ?
(b) Work = W = ?
<u>Solution :</u>
<h2>Question (a) :</h2>In this question , we could use the formula from Second Law of Newton :
Newton's Law of Motion: brainly.com/question/10431582
Example of Newton's Law: brainly.com/question/498822
<h3>Answer details</h3>Grade: High School
Subject: Physics
Chapter: Dynamics
Keywords: Newton, Law, Impulse, Work
Answer:
The viscosity is 1.30 x 10^-3 deca poise.
Explanation:
Volume per minute, V = 10^-5 m^3
Volume per second, V = 1.67 x 10^-7 m^3
density, d = 800 kg/m^3
radius, r = 0.05 cm
Length, L = 0.5 m
Height, h = 60 cm
Pressure, P = h d g = 0.6 x 800 x 9.8 = 4704 Pa
Use the formula of rate of flow