Question

What is the precision (relative error) of the centripetal force divided by the mass if the velocity and the radius are each determined with a precision of 1%

Answer 1

The precision (relative error) of the centripetal force is 1%.

Relative error

This is the error in measurement of a variable obtained in comparison with other variables.

F = mv²/r

where;

• F is centripetal force
• m is mass
• v is velocity
• r is radius

F/m = v²/r

F/m = (0.01v)²/(0.01r)

F/m = 0.01v²/r

F/m = 1%(v²/r)

Thus, the precision (relative error) of the centripetal force is 1%.

Learn more about relative error here: brainly.com/question/13370015