What is the precision (relative error) of the centripetal force divided by the mass if the velocity and the radius are each dete

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2 years ago

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rmined with a precision of 1%

1 answer:

Mrac [35] · Answer 1 · 2022-11-28T11:28:12+03:00

The precision (relative error) of the centripetal force is 1%.

<h3>Relative error</h3>

This is the error in measurement of a variable obtained in comparison with other variables.

F = mv²/r

where;

F/m = v²/r

F/m = (0.01v)²/(0.01r)

F/m = 0.01v²/r

F/m = 1%(v²/r)

Thus, the precision (relative error) of the centripetal force is 1%.

Learn more about relative error here: brainly.com/question/13370015