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Anon25 [30]
3 years ago
13

A scuba diver reaches an elevation of -78 feet, which is a depth of 78 feet.

Mathematics
1 answer:
gavmur [86]3 years ago
6 0

Answer:

true

Step-by-step explanation:

depth is how far down you are from the surface

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The fraction: 340 | 3/4
Effectus [21]

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It's A I hope that helps

Step-by-step explanation:

8 0
3 years ago
4. Find the standard from of the equation of a hyperbola whose foci are (-1,2), (5,2) and its vertices are end points of the dia
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The <em>standard</em> form of the equation of the hyperbola that satisfies all conditions is (x - 2)²/4 - (y - 2)²/5 = 1 .

<h3>How to find the standard equation of a hyperbola</h3>

In this problem we must determine the equation of the hyperbola in its <em>standard</em> form from the coordinates of the foci and a <em>general</em> equation of a circle. Based on the location of the foci, we see that the axis of symmetry of the hyperbola is parallel to the x-axis. Besides, the center of the hyperbola is the midpoint of the line segment with the foci as endpoints:

(h, k) = 0.5 · (- 1, 2) + 0.5 · (5, 2)

(h, k) = (2, 2)

To determine whether it is possible that the vertices are endpoints of the diameter of the circle, we proceed to modify the <em>general</em> equation of the circle into its <em>standard</em> form.

If the vertices of the hyperbola are endpoints of the diameter of the circle, then the center of the circle must be the midpoint of the line segment. By algebra we find that:

x² + y² - 4 · x - 4 · y + 4= 0​

(x² - 4 · x + 4) + (y² - 4 · y + 4) = 4

(x - 2)² + (y - 2)² = 2²

The center of the circle is the midpoint of the line segment. Now we proceed to determine the vertices of the hyperbola:

V₁(x, y) = (0, 2), V₂(x, y) = (4, 2)

And the distance from the center to any of the vertices is 2 (<em>semi-major</em> distance, a) and the semi-minor distance is:

b = √(c² - a²)

b = √(3² - 2²)

b = √5

Therefore, the <em>standard</em> form of the equation of the hyperbola that satisfies all conditions is (x - 2)²/4 - (y - 2)²/5 = 1 .

To learn more on hyperbolae: brainly.com/question/27799190

#SPJ1

5 0
1 year ago
A fraction in which the GCF of the numerator and the denominator is 1 is written in what?
galben [10]
A fraction in which the factor of the numerator and the denominator is 1 is known as a <span>reduced, or simplified, fraction.
</span>
<span>68 is not reduced (or not simplified) because 68 =2⋅32⋅2⋅2 
</span>
<span>34 is a reduced, or simplified, fraction: 1⋅31⋅2⋅2</span>
4 0
3 years ago
7.25t + 6 = 13.5t + 11<br><br><br> The solution is t =
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There’s no picture?sorry can you repost?
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