Angle A is 50 degrees
Angle B is 130 degrees
AB is is 20 feet
        
                    
             
        
        
        
Answer:
a) nearest jump is JL = 1380 inches = 115ft
b) number of jumps in 1 mile N= 46 jumps
Step-by-step explanation:
Given that the jump length is proportional to the body length.
If 2 inch grasshopper can jump 40 inches.
JL = k(BL)
k = JL/BL
where JL = jump length = 40 inches
BL = Body length = 2 inches.
k = 40/2 = 20
The constant of proportionality is 20.
For the athlete :
BL = 5ft 9 inches = 5(12)+9 = 69 inches.
The jump length of the athlete is:
JL = k(BL) = 20(69)
JL = 1380 inches. = 115ft
The number of jumps in 1 mile is
1 mile = 63360 inches
N = 63360/1380
N = 45.9 = 46
N= 46
Therefore, 46 jumps would be needed.
 
        
             
        
        
        
minus 6
Step-by-step explanation:
From 49 to 43 you minus 6
from 43 to 37 you minus 6
Please give me brainliest!
 
        
             
        
        
        
Answer:
(5x-1)^2=16
Step-by-step explanation: