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fgiga [73]
4 years ago
4

Knowledge Check 01 On December 31, management had determined that it would not be able to collect the $1,200 owed to it by one o

f its customers. On Jan 15 in the next year, a check in the amount of $600 was unexpectedly received from this customer. Management does not expect any future collections from this customer. The company uses the direct write-off method to account for its uncollectible accounts. Prepare the necessary journal entry on January 15 to record the events by selecting the account names from the drop-down menus and entering the dollar amounts in the debit or credit columns. Prepare two separate journal entries. The first journal entry is to record the reinstatement of the account receivable and the second is to record the receipt of cash.
Business
1 answer:
SVEN [57.7K]4 years ago
7 0

Answer:

The complete journal entries should be as follows:

December 31 (write off)

Dr Allowance for Doubtful Accounts account 1,200

Cr Accounts Receivable account 1,200

January 15 (partial write off reversing)

Dr Accounts Receivable account 600

Cr Allowance for Doubtful Accounts account 600

January 15 (record collection)

Dr Cash account 600

Cr Accounts Receivable account 600

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In an online survey, Urban Feel, an existing clothing brand, asked its consumers to compare the brand to a musician. The idea be
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The most well-known though contentious psychometric psychological testing method is frequently the projective methodology.

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2 years ago
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Shopping online allows customers to compare prices of many goods and services. This technology will likely:
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3 years ago
Suppose the average return on Asset A is 6.9 percent and the standard deviation is 8.1 percent and the average return and standa
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Answer:

Explanation:

Let us follow this accordingly

a. We have that ;

Z is given as = (X-mean)/standard deviation

where X = 10, mean = 6.9 and standard deviation is 8.1 ------- for A

inputting values we have;

Z = (10-6.9)/8.1 = 0.3827

Using the NORMDIST function in excel, [NORMDIST(0.3827)] = 0.649. This is the probability of earning less than 10%.

Hence the probability of earning more than 10% = 1-0.649 = 0.351 or 35.1%

b. At less than 0%;

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Thus Z = (0-6.9)/8.1 = - 0.8519. Using the NORMDIST function in excel, [NORMDIST(-0.8519)] = 0.1971 or 19.71%.

From this, the probability of earning less than 0% = 19.71%

c. Also For B;

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inputting values gives us ;

Z = (10-4)/3.5 = 1.7143.

Using the NORMDIST function in excel, [NORMDIST(1.7143)] = 0.9568. This is the probability of earning less than 10%.

Which makes the probability of earning more than 10% = 1-0.9568 = 0.0432 i.e 4.32%

d. Als, X = 0.

Giving us;

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This makes the probability of earning less than 10.7%.

Thus required probability gives us = 1-0.9722 = 2.78%

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