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victus00 [196]
4 years ago
5

Suppose the average return on Asset A is 6.9 percent and the standard deviation is 8.1 percent and the average return and standa

rd deviation on Asset B are 4.0 percent and 3.5 percent, respectively. Further assume that the returns are normally distributed. Use the NORMDIST function in Excel to answer the following questions.
a. What is the probability that in any given year, the return on Asset A will be greater than 10 percent? Less than 0 percent? (Round your answers to 2 decimal places. (e.g., 32.16))
Greater than 10 percent %
Less than 0 percent %
b. What is the probability that in any given year, the return on Asset B will be greater than 10 percent? Less than 0 percent? (Round your answers to 2 decimal places. (e.g., 32.16))
Greater than 10 percent %
Less than 0 percent %
c-1 In 1979, the return on Asset A was -4.36 percent. How likely is it that such a low return will recur at some point in the future? (Round your answer to 2 decimal places. (e.g., 32.16))
Probability %
c-2 Asset B had a return of 10.70 percent in this same year. How likely is it that such a high return on T -bills will recur at some point in the future?(Round your answer to 2 decimal places. (e.g., 32.16)
Business
1 answer:
olasank [31]4 years ago
3 0

Answer:

Explanation:

Let us follow this accordingly

a. We have that ;

Z is given as = (X-mean)/standard deviation

where X = 10, mean = 6.9 and standard deviation is 8.1 ------- for A

inputting values we have;

Z = (10-6.9)/8.1 = 0.3827

Using the NORMDIST function in excel, [NORMDIST(0.3827)] = 0.649. This is the probability of earning less than 10%.

Hence the probability of earning more than 10% = 1-0.649 = 0.351 or 35.1%

b. At less than 0%;

X = 0,  mean = 6.9 and standard deviation is 8.1

Thus Z = (0-6.9)/8.1 = - 0.8519. Using the NORMDIST function in excel, [NORMDIST(-0.8519)] = 0.1971 or 19.71%.

From this, the probability of earning less than 0% = 19.71%

c. Also For B;

X = 10%, mean = 4% and standard deviation = 3.5%

inputting values gives us ;

Z = (10-4)/3.5 = 1.7143.

Using the NORMDIST function in excel, [NORMDIST(1.7143)] = 0.9568. This is the probability of earning less than 10%.

Which makes the probability of earning more than 10% = 1-0.9568 = 0.0432 i.e 4.32%

d. Als, X = 0.

Giving us;

Z = (0-4)/3.5 = -1.1429.  

Using the NORMDIST function in excel, [NORMDIST(-1.1429)] = 0.1265 or 12.65%

Thus the probability of earning less than 0% = 12.65%

e. Return on A = -4.36%

Thus z = (-4.36 - 6.9)/8.1 = -1.39. NORMDIST of -1.39 = 0.0822 or 8.22%

f. Return of B = 10.7%

Thus z = (10.7% - 4)/3.5 = 1.9143.

Its NORMDIST = 0.9722

This makes the probability of earning less than 10.7%.

Thus required probability gives us = 1-0.9722 = 2.78%

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Suppose you purchase five put contracts on Testaburger Co. The strike price is $45, and the premium is $3. If, at expiration, th
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Answer:

3000

1500

Explanation:

For each of the answers in this question I have added the formulas to solve them in the attachment below

1.

(45-39)*5*100

= 3000

2.

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7 0
3 years ago
An external competitor to Construction (from another island) is offering to build the new homes for $1300 each. Here are facts a
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Answer:

a. The minimum transfer price (per home) that Construction would be willing to accept would be $1,270

b. The maximum transfer price (per home) Island Evaluations would be willing to accept would be $1,300

Explanation:

a. According to the given data If Construction accepts the proposal of Island Evaluations, then it has to foregone the profits which could have been earned if Construction accepted the proposal of local villagers to build an incline, a bridge and a campground.

Hence, minimum transfer price (per home) for Construction should be such that it covers the profit foregone as given above:

Now, profit foregone is calculated as per the table below:

Figures in $

Particulars Revenue Cost Profit

Incline        1400          600 800

Bridge         1500 950  550

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Total        5600 2750 2850

Therefore, the transfer price should be such which can generate a profit of $2,850 for Construction.

Therefore, total revenue which should be generated = Cost of building five new homes + Profit foregone

= 700*5 + 2850 = $6,350

Hence, minimum transfer price (per home) should be = 6350/5 = $1,270

b. The maximum transfer price (per home) that Island Evaluations will be willing to accept is $1,300 per home as quoted by the external competitor from another island.

4 0
3 years ago
Which of the following would not be an expected response from a decrease in the price level and so help to explain the slope of
Naddik [55]

Answer:

The correct option which would not be an expected response from decrease in price level is A) with fall in prices, Fargo concrete company has decided to let go workers who have fixed price contracts.

Explanation:

All the options except A are expected response from the fall in price and helps in explaining why the aggregate demand curve shifted ( towards the right ) . In the option B , Tyler decided to remodel his kitchen because of fall in prices, as now he is able to spend more on consumption and investment activities. Same thing is happening in option C and D as the company's here are increasing their investment spending due to the decreased prices.

But the option A , isn't something that was expected as company's don't usually fire their workers just because they have fixed price wage contract and prices have fallen, company is trying to take advantage of fallen prices by  reducing the fixed wage workers and hiring new workers on a cheap wage , which help in reducing the company's cost.

6 0
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svp [43]

Answer:

The correct answer is letter "D": Reliability.

Explanation:

In customer care, the quality dimensions refer to a set of five (5) characteristics companies must pay attention to in implementing their operations to attract customers and ensure their loyalty. Those characteristics are: Reliability, Responsiveness, Assurance, Empathy, and Tangibles.

Reliability refers to providing a service the customers can trust. Most consumers prefer traditional methods than innovative because the first has been proven to work. Then, <em>if a university promotes itself as a very traditional campus with an old-world look and feel, where the facilities are manicured and the dorm rooms are large, it is focusing on the reliability aspect of service quality.</em>

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