Answer:
<em>The speed of the plane in still air is 590 mph</em>
<em>The speed of the wind is 20 mph</em>
Step-by-step explanation:
Let's call:
x = Speed of the plane in still air
y = Speed of the wind
The plane traveled d=4575 miles with the wind in t=7.5 h. The speed calculated with this data corresponds to the sum of the speed of the plane and the speed of the wind, thus:
x + y = 610 [1]
The plane traveled 4275 miles in 7.5 hours against the wind, thus the speed calculated is x - y:
x - y = 570 [2]
Adding [1] and [2]:
2x = 610 + 570 = 1180
x = 1180 / 2 = 590
From [1]:
y = 610 - 590 = 20
The speed of the plane in still air is 590 mph
The speed of the wind is 20 mph
Answer:
<h3>9 months</h3>
Step-by-step explanation:
Given the relationship of the dogs weight ang its age modeled by the equation;
w = 6m+4
m represents its age in months, and;
w represents its weight in pounds
Given
w = 58pounds
Required
number of months m before the dog weigh 58pounds;
Substitute w = 58 into the function and get m as shown;
w = 6m + 4
58 = 6m + 4
subtract 4 from both sides
58-4 = 6m+4-4
54 = 6m
divide both sides by 6
54/6 = 6m/6
9 = m
m = 9
Hence it will take 9months before the dog will weigh 58 pounds
Answer:
m = -1/3
Step-by-step explanation:
Find two points in order to calculate slope:
Slope (m) =
ΔY /ΔX= -1/ 3= -0.33333333333333
- ( ΔX = 3 – 0 = 3
- ΔY = 1 – 2 = -1 )
Slope intercept:
y = -0.33333333333333x + 2
