At a school carnival, the diameter of the mat of a trampoline is 16 feet and the diameter of its metal frame is 18 feet. What is the length, in feet, of the metal frame that surrounds the trampoline? Use 3.14 for π and round your answer to the nearest tenth.
2 answers:
Circumference = pi * diametercircumference of metal frame = pi * (diameter of metal frame)(diameter of metal frame) = 12Circumference of Metal Frame = 3.14 * 12 = 37.68therefore D: 37.7 feet would be your answer
18 x 3.14 So the answer would be 56.52ft
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Answer:
x^2/400 + x^2/625
(x-0)^2/400) +(y-0^2/625)
x^2=400
X=sqrt. 400
x = 20
y^2=625
y = sqrt. 625
y= 25
a^2-c^2=b^2
sqrt 400-625 = c
20-25=c
The correct answer is c=-5
(-5,0)
(5,0)
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The answer is letter is C. 19.5 Because you divide
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