It’s a function
hope you have a good day
<span>Answer:
Its too long to write here, so I will just state what I did.
I let P=(2ap,ap^2) and Q=(2aq,aq^2)
But x-coordinates of P and Q differ by (2a)
So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2)
So Q=(2a(p-1), aq^2)
which means, 2aq = 2a(p-1)
therefore, q=p-1
then I subbed that value of q in aq^2
so Q=(2a(p-1), a(p-1)^2)
and P=(2ap,ap^2)
Using these two values, I found the midpoint which was:
M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 )
then x = a(2p-1)
rearranging to make p the subject
p= (x+a)/2a</span>
Answer:
$11040
Step-by-step explanation:
first of all the question says that $4000 were earned in a year and asks for what the new vale would be after the next 3 years with a discount rate of 8%.
If 1 year=$4000,then 3 years=$12000
100%-8%=92% (this happens because there is still a remaining amount that still has a cost to it),so 12000*92%=$11040
Answer:
math amirite is amirite
Step-by-step explanation:
math amirite
x+6 is x+6. It's an expression. Not sure what you need help with.
