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Georgia [21]
4 years ago
14

When NEM is added to a purified solution of creatine kinase, Cys 278 is alkylated, but no other Cys residues in the protein are

modified. What can you infer about the Cys 278 residue based on this observation
Chemistry
1 answer:
USPshnik [31]4 years ago
5 0

Answer:

The answer is given below

Explanation:

Cys 278 residue is the only available cysteine which is alkylated  by the addition of N-Ethylmaleimide or NEM (alkylating agent). It works by only alkylating the sulfhydryls. In this case, Cys 278 residue is the only one which has exposed cysteine residue.

While the other residues have their sulfhydryls group either involved in the synthesis of disulfide bonds of proteins or their Cys residues are intrinsically placed in the proteins and cannot be alkylated with NEM.

NEM cannot alkylate if its protein is not available in the free form or it is in bounded form. For NEM to alkylate Cys 278, it should be free and should have sulfhydryls available for alkylation.

Alkylation: it is the transfer of alkyl groups. Alkyl groups contain Hydrogen and Carbon in their structure.

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A sample of 10.0 grams of carbon dioxide gas is contained in a tank with a volume of 6.0 L so that the pressure inside the tank
Snezhnost [94]

Answer:

49°C

Explanation:

Let's apply the Ideal Gases Law in order to solve this question:

P . V = n . R . T

Pressure = 1 atm

Volume = 6 L

n = number of moles → 10 g. 1mol /44g = 0.227 moles

R = Ideal Gases Constant

We replace data: 1 atm . 6 L = 0.227 mol . 0.082 . T

6 atm.L / ( 0.227 mol . 0.082) = T

T° = 322 K

We convert T° from K to °C → 322 K - 273 = 49°C

7 0
3 years ago
How many molecules are in 20.0 L(liters) of SO2 at STP
Finger [1]

5.4 x 10²³ molecules

Explanation:

Given parameter

Volume of gas = 20L

Condition of reaction = STP

Unknown:

number of molecules

Solution:

The number of molecules of a substance is given by;

   Number of molecules = Number of moles x avogadro's constant

Number of moles at stp = \frac{volume of gas}{22.4}

 Number of moles of SO₂ = \frac{20}{22.4} = 0.893mole

Number of molecules = 0.893 x 6.02 x 10²³ = 5.4 x 10²³ molecules

learn more:

Number of molecules brainly.com/question/10818009

#learnwithBrainly

4 0
3 years ago
How many valence electrons does aluminum have.
Marysya12 [62]

Answer:

3 valence electrons

Explanation:

Aluminum has three valence electrons. Valence electrons are found in the outermost shell of an element and are responsible for its valence.

4 0
3 years ago
If a sample of 4 moles of gas has a pressure of 567.42 kPa and a volume of 12.0 L, what is it's temperature?
Lady_Fox [76]
Your answer is b, hope this helps ;)
7 0
3 years ago
Read 2 more answers
Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.10 g of ethane is
puteri [66]

Answer:

Ethane is the limiting reactant, so no mass of ethane will be left over by the chemical reaction. All the mass will react, the 2.1 grams of ethane.

Explanation:

First of all, we need to determine the reaction and the limiting reactant to work with the stoichiometry.

The equation is: 2C₂H₆ + 7O₂ →  4CO₂ + 6H₂O

We define the moles of the reactants:

2.10 g / 30 g/mol = 0.07 moles of ethane

12 g / 32 g/mol = 0.375 moles of oxygen

To determine the limiting reactant, we start with oxygen:

7 moles of O₂ can react with 2 moles of ethane

Then, 0.375 moles of O₂ will react with (0.375 . 2) / 7= 1.31 moles of ethane.

We do not have enough ethane, just only 0.07 moles to react.

Ethane is the limiting reactant, so no mass of ethane will be left over by the chemical reaction. All the mass will react, the 2.1 grams of ethane.

7 0
3 years ago
Read 2 more answers
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