Answer:
B.0.2 J/g°C
Explanation:
From the attached picture;
- Heat attained in the solid phase is 200 Joules
- Change in temperature is 50°C ( from 0°C to 50°C)
- Mass of the solid is 20 g
We are required to determine the specific heat capacity of the substance;
- We need to know that Quantity of heat is given by the product of mass,specific heat capacity and change in temperature.
- That is; Q = mcΔT
Rearranging the formula;
c = Q ÷ mΔT
Therefore;
Specific heat = 200 J ÷ (20 g × 50°c)
= 0.2 J/g°C
Thus, the specific heat of the solid is 0.2 J/g°C
Graduated cylinders or beakers.
Answer:
<h2>
= (
1.08 /
2.2
) 100% = 49%</h2>
Explanation:
Balanced Equation: 2CH₃CH₃(g) + 5O₂(g) → 2CO₂(g) + 6H₂O(g)
Calculate moles of CH₃CH₃ and O₂
1.2 ₃₃ (
1 ₃₃/
30.0694 ₃₃
) = 0.040 ₃₃
8.6 ₂ (
1 2/
31.998 ₂
) = 0.27 ₃₃
Find limiting reagent 0.040 ₃₃ (
5 ₂/
2 ₃₃
) = 0.10 ₂
CH₃CH₃ is the limiting Reagent
CH₃CH₃ (L.R.) O₂ CO₂ H₂O
Initial (mol) 0.040 0.27 0 0
Change
(mol)
-2x=-0 -5x=
-0.10 +2x=+0.040 +6x=+0.12
Final (mol) 0 0.117 0.040 0.12
0.040 − 2 = 0 = 0.020
Determine percent yield
0.12 ₂ (
18.0148 ₂
/1 ₂
) = 2.2 ₂
= (
1.08 /
2.2
) 100% = 49%
We first need to find the number of moles of gas in the container
PV = nRT
where;
P - pressure - 2.87 atm x 101 325 Pa/atm = 290 802.75 Pa
V - volume - 5.29 x 10⁻³ m³
n - number of moles
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 230 K
substituting these values in the equation
290 802.75 Pa x 5.29 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 230 K
n = 0.804 mol
the molar mass = mass present / number of moles
molar mass of gas = 56.75 g / 0.804 mol
therefore molar mass is 70.6 g/mol
The density told you the mass covered by one unit of volume of that substance.
Density defines how perfectly the molecules of a substance are packed in a unit of volume.
In the given problem the substances are expressed in g/ml which means that a unit of volume will be 1 mL.
Given ,
Density of mercury = 13.546 g/ml
It means 1mL of mercury will have a mass of 13.546 g, Similarly 1 mL of ethanol will have a mass of 0.789 g.
0.350 L * 10^3 ml/1 L* 13.546/1 mL = 4,741.1 g
The volume of ethanol will have an equal mass is
4741.1 g* 1 mL/0.789g = 6,008.9 mL
6,008.9 mL* 1L/10^3mL = 6.0081 L
Hence the answer is 6.0081 L
To know more about density occupies here :
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