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anyanavicka [17]
3 years ago
13

Factor the expression over the complex numbers. x2+20

Mathematics
2 answers:
vovangra [49]3 years ago
6 0
X²+20=0
x=±√(-80)/2
x=±4i√5/2=2i√5

factorised it is then
(x+2i√5)*(x-2i√5)
Blababa [14]3 years ago
4 0

Answer:

x^2+20=(x-2\sqrt{5}i)(x+2\sqrt{5}i)  

Step-by-step explanation:

Given : Expression x^2+20

To find : Factor the expression over the complex numbers ?

Solution :

To factor we equate the expression to zero.

x^2+20=0

Subtract 20 both side,

x^2+20-20=-20

x^2=-20

Taking root both side,

x=\sqrt{-20}

x=\pm 2\sqrt{5}i

The factor of the expression is x^2+20=(x-2\sqrt{5}i)(x+2\sqrt{5}i)

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3 years ago
The difference of the square of a number and 40 is equal to 3 times that number. Find the positive solution.
Wewaii [24]

Answer: The answer is 8.

Step-by-step explanation: The first step is to convert the expression into figures. We shall call the unknown number Y. So if we are told “the square of a number,” that means Y squared, or better still, Y^2. Further we are told “the difference between the square of a number and 40” and that can be written as;

Y^2 - 40.

Next we are told that this expression is equal to 3 times that number (that is 3Y). That can now be written out as follows,

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If we move all expressions to one side of the equation, what we would have is,

Y^2 - 3Y -40 = 0

(Remember that when a positive value crosses to the other side of an equation it becomes negative and vice versa)

We now have a quadratic equation

Y^2 -3Y - 40 = 0

By factorizing we now have

(Y -8) (Y + 5) = 0

Therefore Y - 8 = 0 or

Y + 5 = 0

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5 0
3 years ago
Write an absolute value inequality that has 3 and -5 as two of its solutions
tino4ka555 [31]
Absolute value makes all things inside positive (make result positive)
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if -5
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treu
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Answer:

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Step-by-step explanation:

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