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ratelena [41]
3 years ago
13

At East High School, 60% of the students voted in an election. If there are 1500 students, How many voted?​

Mathematics
2 answers:
sukhopar [10]3 years ago
3 0
900 students voted in the election
mario62 [17]3 years ago
3 0

Answer:

900 student voted!

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Please hurry please
Elza [17]

Answer:

C is greater than or equal to 20, so the answer is C=20

3 0
2 years ago
Calculate the limit values:
Nataliya [291]
A) This particular limit is of the indeterminate form,
\frac{ \infty }{ \infty }
if we plug in infinity directly, though it is not a number just to check.

If a limit is in this form, we apply L'Hopital's Rule.

's
Lim_{x \rightarrow \infty } \frac{ ln(x ^{2} + 1 ) }{x} = Lim_ {x \rightarrow \infty } \frac{( ln(x ^{2} + 1 ) ) '}{x ' }
So we take the derivatives and obtain,

Lim_ {x \rightarrow \infty } \frac{ ln(x ^{2} + 1 ) }{x} = Lim_{x \rightarrow \infty } \frac{ \frac{2x}{x^{2} + 1} }{1}

Still it is of the same indeterminate form, so we apply the rule again,

Lim_{x \rightarrow \infty } \frac{ ln(x ^{2} + 1 ) }{x} = Lim_{x \rightarrow \infty } \frac{ 2 }{2x}

This simplifies to,

Lim_{x \rightarrow \infty } \frac{ ln(x ^{2} + 1 ) }{x} = Lim_{x \rightarrow \infty } \frac{ 1 }{x} = 0

b) This limit is also of the indeterminate form,

\frac{0}{0}
we still apply the L'Hopital's Rule,

Lim_ {x \rightarrow0 }\frac{ tanx}{x} = Lim_ {x \rightarrow0 } \frac{ (tanx)'}{x ' }

Lim_ {x \rightarrow0 }\frac{ tanx}{x} = Lim_ {x \rightarrow0 } \frac{ \sec ^{2} (x) }{1 }

When we plug in zero now we obtain,

Lim_ {x \rightarrow0 }\frac{ tanx}{x} = Lim_ {x \rightarrow0 } \frac{ \sec ^{2} (0) }{1 } = \frac{1}{1} = 1
c) This also in the same indeterminate form

Lim_ {x \rightarrow0 }\frac{ {e}^{2x} - 1 - 2x}{ {x}^{2} } = Lim_ {x \rightarrow0 } \frac{ ({e}^{2x} - 1 - 2x)'}{( {x}^{2} ) ' }

Lim_ {x \rightarrow0 }\frac{ {e}^{2x} - 1 - 2x}{ {x}^{2} } = Lim_ {x \rightarrow0 } \frac{ (2{e}^{2x} - 2)}{ 2x }

It is still of that indeterminate form so we apply the rule again, to obtain;

Lim_ {x \rightarrow0 }\frac{ {e}^{2x} - 1 - 2x}{ {x}^{2} } = Lim_ {x \rightarrow0 } \frac{ (4{e}^{2x} )}{ 2 }

Now we have remove the discontinuity, we can evaluate the limit now, plugging in zero to obtain;

Lim_ {x \rightarrow0 }\frac{ {e}^{2x} - 1 - 2x}{ {x}^{2} } = \frac{ (4{e}^{2(0)} )}{ 2 }

This gives us;

Lim_ {x \rightarrow0 }\frac{ {e}^{2x} - 1 - 2x}{ {x}^{2} } =\frac{ (4(1) )}{ 2 }=2

d) Lim_ {x \rightarrow +\infty }\sqrt{x^2+2x}-x

For this kind of question we need to rationalize the radical function, to obtain;

Lim_ {x \rightarrow +\infty }\frac{2x}{\sqrt{x^2+2x}+x}

We now divide both the numerator and denominator by x, to obtain,

Lim_ {x \rightarrow +\infty }\frac{2}{\sqrt{1+\frac{2}{x}}+1}

This simplifies to,

=\frac{2}{\sqrt{1+0}+1}=1
5 0
3 years ago
Match the equation with its graph 15x -12y=60
IgorLugansk [536]

Answer:

Check the attached graph for correct match.

Step-by-step explanation:

Graph of the given choices are not given but we can still solve this problem.

Given equation is  15x-12y=60.

Which is linear equation so we need at least two points to get the graph.

We are free to select any random number of x then plug that into given equation to find other variable.

Let's use x=0

15x-12y=60

15*0-12y=60

0-12y=60

-12y=60

divide both sides by -12

y=-5

Hence point is (0,-5)

Similarly plug y=0

15x-12y=60

15x-12*0=60

15x-0=60

15x=60

divide both sides by 15

x=4

Hence point is (4,0)

Now graph both points then join them by a straight line.

Any graph given in the choices which match with attached graph will be the answer.

Check the attached graph for correct match.

6 0
2 years ago
Al drives from York toward Benton at 45 mph, and Ben drives from Benton toward York at 55 mph. If York and Benton are 210 miles
Pepsi [2]
In this question, <span>Al drives from York toward Benton and Ben drives from Benton toward York. That means both Al and Ben will reduce the distance between them. In this case, you need to add their velocity. The total velocity should be 45mph+55mph= 100mph

The distance will be shortened by 100mile/hour and the distance is 210 miles. Then the time should be:
time=distance/total velocity =210m/100mph= 2.1 hours </span>
5 0
3 years ago
Read 2 more answers
What does x equal in x^3-9x+1=0
12345 [234]
X^3 -9x+1= 0 (minus 1)

X^3-9x=-1 (divide by 9)

x^3-x=-1/9

But it doesn’t work any further so you have written it wrong
5 0
2 years ago
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