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Ksenya-84 [330]
3 years ago
6

You want to place a towel bar that is 10 1⁄4 inches long in the center of a door that is 26 1⁄3 inches wide. How far should you

place the bar from each edge of the door? (Write the answer as a mixed number.)
Mathematics
1 answer:
djverab [1.8K]3 years ago
8 0
First we want to find the part of the door not covered by the towel bar.

So subtract 10.25 from 26.33

In order to do this we need common denominators

So we multiply the fractions to get

(26 & 4/12) - (10 & 3/12)

Now we subtract to get

15 & 1/12

Since the 15 is odd, add 12/12 to the fraction

14 & 13/12

Now divide that in half to get the distance from each edge

7 & 13/24
You might be interested in
Jason ha 2,057 stones in his collection.
Rashid [163]

Answer:

2560 stones

Step-by-step explanation:

Jason has 2057 stones

Paul's stones = Jason + 503

= 2057 + 503 = 2560

5 0
3 years ago
I NEED HELP QUICKLY!!! What is the sum of the first 140 positive multiples of 3?
garri49 [273]

Answer:

C

Step-by-step explanation:

The multiples of 3 are

3, 6, 9, 12, 15, ...........

The terms form an arithmetic sequence with common difference of 3.

The sum to n terms is

S_{n} = \frac{n}{2} [2a₁ + (n - 1)d ]

where a₁ is the first term and d the common difference

Here a₁ = 3 and d = 3, thus

S_{140} = \frac{140}{2} [ (2 × 3) + (139 × 3) ]

                            = 70(6 + 417) ] = 70 × 423 = 29610 → C

5 0
3 years ago
How Do I solve this I am quite confused
Kazeer [188]

Answer:

$11,714

Step-by-step explanation:

C(x) = 0.7x² - 462x + 87,944

this is a quadratic equation that opens up

the vertex will be the minimum

From the quadratic formula the x coordinate of the vertex is

x = -b/2a

x = 462/(2 * 0.7)

x = 330

Plug in

c(330) = 0.7(330²) - 462(330) + 87,944

c(330) = 11,714

$11,714

5 0
3 years ago
What is the area of a rectangle that has side lengths of 3/4 yard and 5/6 yard
Ahat [919]

We are asked to find the area of the rectangle that has side lengths of 3/4 yard and 5/6 yard.

We know that area of rectangle is width times length.

To find the area of the given rectangle we will multiply both side lengths as:

\text{Area of rectangle}=\text{Width}\times \text{Length}

\text{Area of rectangle}=\frac{3}{4}\text{ yard}\times\frac{5}{6}\text{ yard}

\text{Area of rectangle}=\frac{3}{4}\times\frac{5}{6}\text{ yard}^2

\text{Area of rectangle}=\frac{1}{4}\times\frac{5}{2}\text{ yard}^2

\text{Area of rectangle}=\frac{1\times5}{4\times2}\text{ yard}^2

\text{Area of rectangle}=\frac{5}{8}\text{ yard}^2

Therefore, the area of the given rectangle would be \frac{5}{8} square yards.

5 0
3 years ago
In a quadrilateral ABCD, AB || DC and AD || BC. Find the perimeter of triangle COD if the diagonals of the quadrilateral interse
aalyn [17]
Draw a diagram as shown below.

The diagonals are equal in length. Because AB || DC and AD || BC, the quadrilateral is a square.

Because the diagonals bisect each other at O, therefore
DO = BO = 10.
Likewise,
AO = CO = 10

Because AB = 13, therefore DC = 13.
The perimeter of ΔCOD is CO + CD + DO = 10 + 13 + 10 = 33 in

Answer: 33 in

4 0
3 years ago
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