Ask question

Ask question

All categories

3 years ago

11

Which of the following is a counterexample to "the sum of two numbers is always greater than either of the numbers"?

1 answer:

Butoxors [25]3 years ago

8 0

Which of what following?

You might be interested in

A bag contains tickets numbered 1 through 5. Use the probability distribution to determine the probability of drawing an odd num

Makovka662 [10]

Answer:

The probability of drawing an odd numbered ticket is 60%.

Step-by-step explanation:

Odd numbered tickets:

Probability of one is 1/5 plus half of 1/5.

$P(X = 1) = \frac{1}{5} + \frac{1}{10} = \frac{3}{10}$

Probability of 3 is half of 1/5.

$P(X = 3) = \frac{1}{10}$

Probability of 5 is 1/5. So

$P(X = 5) = \frac{1}{5}$

Probability of drawing an odd numbered ticket:

$p = P(X = 1) + P(X = 3) + P(X = 5) = \frac{3}{10} + \frac{1}{10} + \frac{1}{5} = \frac{4}{10} + \frac{2}{10} = \frac{6}{10} = 0.6$

0.6*100% = 60%

The probability of drawing an odd numbered ticket is 60%.

3 0

3 years ago

Tower one, a cube with a hexagonal prism measures 15.6cm. Tower two, a cube with a cylinder measures 18.3cm. Tower 3, a hexagona

lina2011 [118]

Answer:

$Tower 4 = 23.9cm$

Step-by-step explanation:

Given

Tower one = 15.6 cm

Tower two = 18.3 cm

Tower 3 = 13.9 cm.

Required:

Height of the 4th tower

Represent a cube by X; a cylinder by Y and a hexagonal prism by Z

Tower one, a cube with a hexagonal prism = X + Z = 15.6

Tower two, a cube with a cylinder = X + Y = 18.3

Tower 3, a hexagonal prism with a cylinder = Z + Y = 13.9

$X + Z = 15.6$ ----- Equation 1

$X + Y = 18.3$ ----- Equation 2

$Z + Y = 13.9$ ----- Equation 3

Subtract equation 1 from 2

$(X + Y = 18.3) - (X + Z = 15.6)$

$X - X + Y - Z = 18.3 -15.6$

$Y - Z = 18.3 -15.6$

$Y - Z = 2.7$ ---- Equation 4

Add Equation 4 to Equation 3

$(Y - Z = 2.7) + (Z + Y = 13.9)$

$Y + Y - Z + Z = 2.7+ 13.9$

$2Y = 2.7+ 13.9$

$2Y = 16.6$

Divide both sides by 2

$\frac{2Y}{2} = \frac{16.6}{2}$

$Y = \frac{16.6}{2}$

$Y = 8.3cm$

Substitute $Y = 8.3cm$ in Equation 2 and 3

$X + Y = 18.3$ ----- Equation 2

$X + 8.3 = 18.3$

Subtract 8.3 from both sides

$X + 8.3 - 8.3 = 18.3 - 8.3$

$X = 18.3 - 8.3$

$X = 10cm$

$Z + Y = 13.9$ ----- Equation 3

$Z + 8.3 = 13.9$

Subtract 8.3 from both sides

$Z + 8.3 - 8.3 = 13.9 - 8.3$

$Z = 13.9 - 8.3$

$Z = 5.6cm$

So, we have that

$X = 10cm$

$Y = 8.3cm$

$Z = 5.6cm$

The question states that the 4th tower is made up of the three shapes;

This implies that;

$Tower 4 = X + Y + Z$

$Tower 4 = 10cm + 8.3cm + 5.6cm$

$Tower 4 = 23.9cm$

The height of the 4th tower is 23.9cm

8 0

3 years ago

You need to put your reindeer, Rudy, Ezekiel, Gloopin, Bloopin, and Prancer, in a single-file line to pull your sleigh. However,

topjm [15]

If the reindeer do not fight, there are 5!=120 ways to line them up in a straight line.
Out of these, Bloopin and Rudy are together in 4!=24 times. Similarly Rudy and Bloopin will be together 4!=24 times. So the number of ways they are not together is 120-24-24=72 ways.

6 0

3 years ago

6x^3+ 10x^2 – 4x<br> -<br> I need help with this question

Westkost [7]

Answer: 2x(3x−1)(x+2)

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Simplify: -4 2/10 - (-13 1/10)

tamaranim1 [39]

Answer:

The answer is 8 9/10

Step-by-step explanation:

hope this helps

4 0

3 years ago

Read 2 more answers