Answer:
I think its 336. I might be wrong though, But I hope I am right.
Step-by-step explanation:
The distance travelled by the train with constant speed of r miles will be 3r.
<h3><u>
What is Speed?</u></h3>
- The most crucial scientific notion is measurement. Base or physical fundamental units are used to quantify a wide range of quantifiable quantities.
- One such measurable metric is speed, which calculates the ratio between the distance an object travels and the time needed to cover that distance. Let's explore speed in-depth in this session.
- The pace at which an object's location changes in any direction. When an object travels the same distance in the same amount of time, it is said to be moving at a uniform speed.
- When an object travels a different distance at regular intervals, it is said to have variable speed.
We know the formula of distance linking the speed and the time.
Distance = speed × time
Substituting the given values to get:
Distance = r × 3
Distance = 3r
Know more about Speed with the help of the given link:
brainly.com/question/6280317
#SPJ4
Answer:
The equation you would use is лr² (pi times radius squared).
The area of the stage would be 1963.5 square meters or 625л square meters
AB = ==> distance between the bottom of the plank; and the wall ===> 3 ft.
C ====> 49 degrees
For letter a, to solve for AC:
AC ==> HYPOTENUSE. The angle C is the OPPOSITE side of AB.
use sine :
sin A ===> opposite/hypotenuse
Solve:
sin 49 ====> 3/AC
AC ====> 3 / sin 49
AC ====> 3.96 ft.
For letter b, to solve for BC:
We are now given with the base (3 ft.); and; the hypotenuse (3.96 ft.) so we can use the Pythagorean theorem:
a^2 + b^2 = c^2
Let:
a ===> AB
b ===> BC
c ===> AC
(AB)^2 + (BC)^2 ===> (AC)^2
3^2 + (BC)^2 ===> (3.96)^2
(BC)^2 ===> (3.96)^2 - 3^2
(BC)^2 ===> 6.6816
sqrt (BC)^2 ===> sqrt 6.6816
Answer: BC ===> 2.58 ft.
Hope that helps!!!! : )
Answer:
(1, 10)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
-5x + 6y = 55
4x + 3y = 34
<u>Step 2: Rewrite Systems</u>
4x + 3y = 34
- Multiply everything by -2: -8x - 6y = -68
<u>Step 3: Redefine Systems</u>
-5x + 6y = 55
-8x - 6y = -68
<u>Step 4: Solve for </u><em><u>x</u></em>
<em>Elimination</em>
- Combine equations: -13x = -13
- Divide -13 on both sides: x = 1
<u>Step 5: Solve for </u><em><u>y</u></em>
- Define equation: 4x + 3y = 34
- Substitute in <em>x</em>: 4(1) + 3y = 34
- Multiply: 4 + 3y = 34
- Isolate <em>y</em> term: 3y = 30
- Isolate <em>y</em>: y = 10
