Answer:
512
Step-by-step explanation:
You are multiplying the bottom two numbers connected to the box on top.
In this case, multiply 64 with 8:
64 * 8 = 512
512 is your answer.
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Hello!
The discriminant of quadratic functions is: b² - 4ac. Since the equation is in standard form, which is Ax² + Bx + C = 0 , we can substitute those values into our discriminant and simplify.
The value of the discriminant will tell us how many solutions there are to the given quadratic equation.
A positive discriminant will have two real solutions.
A discriminant of zero will have one real solution.
A negative discriminant will no real solutions.
1. Substitute, a = 16, b = 8, c = 1.
8² - 4(16)(1)
64 - 4(16)(1)
64 - 64(1)
64 - 64
0
Since the discriminant is zero, the answer is choice A, double root, because since it is raised to the power of 2, it must has two roots, but in this case, both of the roots the same x-values.
Answer:
Emma can complete the calls alone in 6 days, which means she can complete 
of the calls in one day. So, Emma’s rate per day is . Jackson can complete the calls alone in 
days, which means he can complete 
of the calls in one day. So, Jackson’s rate per day is . Because they’re working together, the time, 
, is the same for both.
Multiply across the table to find the part of the task each has completed. Use the equation work completed = (rate)(time) to fill in the last column cells.
Step-by-step explanation:
Use photomath it’s more easy
Answer:
Step-by-step explanation:
The question to be solved is the following :
Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, and that γ is unique if 
. Recall that given two vectors a,b a⊥ b if and only if 
where 
is the dot product defined in 
. Suposse that 
. We want to find γ such that 
. Given that the dot product can be distributed and that it is linear, the following equation is obtained
Recall that 
are both real numbers, so by solving the value of γ, we get that
By construction, this γ is unique if 
, since if there was a 
such that 
, then
