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N76 [4]
3 years ago
8

This is the problem:

Mathematics
2 answers:
natta225 [31]3 years ago
8 0
Sophie has 3x candies
they have 4 x together 
sophie has 2x more than lisa
EastWind [94]3 years ago
3 0
Sophie: 3x
Sophie has 2x candies more than lisa
Sophie and lisa have 4x candies
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Solve each equation? (n+2) ( n+1)= 0
Delicious77 [7]

Answer:

n=-2,\:n=-1

Step-by-step explanation:

\left(n+2\right)\left(n+1\right)=0\\\mathrm{Using\:the\:Zero\:Factor\:Principle:\quad \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)\\\mathrm{Solve\:}\:n+2=0:\quad n=-2\\n+2=0\\\mathrm{Subtract\:}2\mathrm{\:from\:both\:sides}\\n+2-2=0-2\\\mathrm{Simplify}\\n=-2\\\mathrm{Solve\:}\:n+1=0:\quad n=-1\\n+1=0\\\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}\\n+1-1=0-1\\Simplify\\n=-1\\\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}\\n=-2,\:n=-1

7 0
3 years ago
Read 2 more answers
find the value of c that makes each trinomial a perfect square. then write the trinomial as a perfect square. the equation , x^2
mr Goodwill [35]
Therefore, the value of C should be (11/2)^2

<span>To square a fraction, take the square of the numerator and put it over the square of the denominator. So since 11^2=121 and 2^2=4, (11/2)^2
(11)^2/(2)^2=121/4
</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
3 0
3 years ago
The leader board at the Lakeside Golf Tournament shows that Mei's score is 3
weeeeeb [17]
Part A.) the answer is B:9
Part B.) together their total score is -3
4 0
4 years ago
Please help logarithms!
nlexa [21]

Given:

\log_34\approx 1.262

\log_37\approx 1.771

To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

We have,

\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

\log_3\left(\dfrac{4}{49}\right)=1.262-3.542

\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

5 0
3 years ago
Which of the is the same as2.3×10^3
dalvyx [7]
2300 you mover the decimal over 3 spaces
7 0
4 years ago
Read 2 more answers
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