You have $15 and admission is $5, so you know have $10 before doing any games. If you wanted to play 12 games, you would need $10.20, which you do not have. But, if you wanted to play 11 games, then you would need $9.35, which is just under $10.
So the maximum amount of games that you could play would be 11 games.
Answer:
2. n = 11
4. g = -2
6. t = 21
8. n = 4
10. y = -1
Step-by-step explanation:
2. 63 = -3(1 - 2n)
Dividing both the side by negative 3 we get
4. -g + 2(3 + g) = -4(g + 1)
First we will open the bracket by distributive property A( B +C) = AB + AC
6.-3(t +5 ) + (4t + 2) = 8
Using distributive property A( B +C) = AB + AC we get
8. -8 - n = -3(2n -4)
Using distributive property A( B +C) = AB + AC we get
10. -4( 2 - y) + 3y = 3(y - 4)
Using distributive property A( B +C) = AB + AC we get
Yes; you are correct.
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The correct answer is:
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Answer choice: [C]: " x³ − 9x² + 23x <span>− 12 " .
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Note: (a </span>− b) (c − d + e) = ac − ad + ae − bc + bd − be ;
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(x − 4) (x² <span>− 5x + 3) =
x * x</span>² = x³ <span>−
x * 5x = 5x</span>² +
x * 3 = 3x <span>−
4 * x</span>² = 4x² <span>−
-4 * 5x = -20x +
-4 * 3 = -12;
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</span> (x − 4) (x² − 5x + 3) =
x³ − 5x² + 3x −4x² − (-20x) + (-12) ;
= x³ − 5x² + 3x −4x² + 20x − 12 ;
= x³ − 5x² − 4x² + 3x + 20x − 12 ;
= x³ − 9x² + 23x − 12 ; which is:
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Answer choice: [C]: " x³ − 9x² + 23x − 12 " .
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Three or more points on a straight line
