4m^2×4m^3. how do i put this as a single power
1 answer:
You might be interested in
Answer:
True
Step-by-step explanation:
A six sigma level has a lower and upper specification limits between and
. It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:
For those with defects <em>operating at a 6 sigma level, </em>the probability is:
Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:
.
The probability of defects is:
Well, the defects present in a six sigma level and a five sigma level are, respectively:
Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>
[1]
[2]
Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.
Given:
The data values are:
7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19
To find:
The outliers of the given data set.
Solution:
We have,
7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19
Divide the data set in two equal parts.
(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)
Divide each parenthesis in two equal parts.
(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)
Now,
And
The interquartile range is:
The data values lies outside the interval are known as outliers.
All the data values lie in the interval [6,22]. So, there are no outliers.
Hence, the correct option is 4.