If a plane loses 1400 feet in altitude over a horizontal distance of 8000 feet what is the slope?

The points (–2, 4) and (–2, –2) are vertices of a heptagon. Explain how to find the length of the segment formed by these endpoi

Scrat [10]

Answer:

The segment is 6 units long.

Step-by-step explanation:

The points (–2, 4) and (–2, –2) are vertices of a heptagon. We have to explain how to find the length of the segment formed by these endpoints.

If two points at the ends of a straight line PQ are P( $x_{1},y_{1}$ ) and Q( $x_{2},y_{2}$ ), then the length of the segment PQ will be given by the formula

$\sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2}}$

Now, in our case the two points are (-2,4) and (-2,-2) and the length of the segment will be

$\sqrt{(- 2 - (- 2))^{2} + (4 - (- 2))^{2}} = 6$ units. (Answer)

5 0

3 years ago

Read 2 more answers

This is a 3 part 1 question each part on how to locate the plane and a small explanation report working out the recovery details

sesenic [268]

Third leg.

The crew flies at a speed of 560 mi/h in direction N-20°-E.

The wind has a speed of 35 mi/h and a direction S-10°-E.

We then can draw this as:

We have to add the two vectors to find the actual speed and direction.

We will start by adding the x-coordinate (W-E axis):

$\begin{gathered} x=560\cdot\sin (20\degree)+35\cdot\sin (10\degree) \\ x\approx560\cdot0.342+35\cdot0.174 \\ x\approx191.53+6.08 \\ x\approx197.61 \end{gathered}$

and the y-coordinate (S-N axis) is:

$\begin{gathered} y=560\cdot\cos (20\degree)-35\cdot\cos (10\degree) \\ y\approx560\cdot0.940-35\cdot0.985 \\ y\approx526.23-34.47 \\ y\approx491.76 \end{gathered}$

Then, the actual speed vector is v3=(197.61, 491.76).

The starting location for the third leg is R2=(216.66, 167.67) [taken from the previous answer].

Then, we have to calculate the displacement in 20 minutes using the actual speed vector.

We can calculate the movement in each of the axis. For the x-axis:

$\begin{gathered} R_{3x}=R_{2x}+v_{3x}\cdot t \\ R_{3x}=216.66+197.61\cdot\frac{1}{3} \\ R_{3x}=216.66+65.87 \\ R_{3x}=282.53 \end{gathered}$

NOTE: 20 minutes represents 1/3 of an hour.

We can do the same with the y-coordinate:

$\begin{gathered} R_{3y}=R_{2y}+v_{3y}\cdot t \\ R_{3y}=167.67+491.76\cdot\frac{1}{3} \\ R_{3y}=167.67+163.92 \\ R_{3y}=331.59 \end{gathered}$

The final position is R3 = (282.53, 331.59).

To find the distance from the origin and direction, we transform the cartesian coordinates of R3 into polar coordinates:

The distance can be calculated as if it was a right triangle:

$\begin{gathered} d^2=x^2+y^2_{} \\ d^2=282.53^2+331.59^2 \\ d^2=79823.20+109951.93 \\ d^2=189775.13 \\ d=\sqrt[]{189775.13} \\ d\approx435.63 \end{gathered}$

The angle, from E to N, can be calculated as:

$\begin{gathered} \tan (\alpha)=\frac{y}{x} \\ \tan (\alpha)=\frac{331.59}{282.53} \\ \tan (\alpha)\approx1.1736 \\ \alpha=\arctan (1.1736) \\ \alpha=49.56\degree \end{gathered}$

If we want to express it from N to E, we substract the angle from 90°:

$\beta=90\degree-\alpha=90-49.56=40.44\degree$

Answer: the final location can be represented with the vector (282.53, 331.59).

1) The distance from the origin is 435.63 miles and

2) the direction is N-40°-E.

7 0

10 months ago

the perimeter of a semicircle is 108 cm what is the perimeter of the square drawn on the diameter of the semicircle

Andreas93 [3]

Answer:

Step-by-step explanation:

the perimeter of the semi-circle would be the diameter plus the circumference of half of the circle.

They want to know the perimeter of a square using the diameter of the sem-circle as ONE side, so the perimeter of the square would be 4 times the ONE side.

We should recall:

diameter = 2 times the radius circumference of a cirlce = 2π r

How do we find the diameter of the of the semi circle?

The perimeter of the semi circle is given as 108 cm

Perimeter of the semicirle = 2r + π r diameter plus semi circumference

108 = r ( 2 + π) factor out the r and solve for r

108 / (2 + π) = r divide both sides by ( 2 + r)

Now we know r, the perimeter of the squqre is 4 times 2r or 8r

perimeter of square = 8 [ 108 / (2 + π) ] π I used 3.14

= 864 / 5.14

= 168.1 cm I got rounded to nearest tenth

When I re-checked by work I found a few math, logic and calculation errors. Please re-check my answer for any more mistakes.

4 0

3 years ago

What was the mistake? *

seropon [69]

Answer

Step-by-step explanation:

4 0

3 years ago

(5 + 4) + (2 + 6) = 10 +__ Find the missing number.

LUCKY_DIMON [66]

Answer:

The Missing number is 7

Step-by-step explanation:

5+4=9

2+6=8

9+8=17

And if the equations are supposed to have the same answer then you add 7 to 10 and they both have the same answer.

Could I please have BRAINLIEST.

4 0

3 years ago