Given:
The vertex of a quadratic function is (4,-7).
To find:
The equation of the quadratic function.
Solution:
The vertex form of a quadratic function is:
...(i)
Where a is a constant and (h,k) is vertex.
The vertex is at point (4,-7).
Putting h=4 and k=-7 in (i), we get


The required equation of the quadratic function is
where, a is a constant.
Putting a=1, we get

![[\because (a-b)^2=a^2-2ab+b^2]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a-b%29%5E2%3Da%5E2-2ab%2Bb%5E2%5D)
Therefore, the required quadratic function is
.
x² + y² = 9 is the equation of a circle with center (0, 0) and radius 3.
This puts the vertices at (-3, 0), (3, 0), (0, -3), and (0, 3).
When is the tangent line vertical? <em>when it passes through the x-axis.</em>
Answer: (-3, 0), (3, 0)
Answer:
Option C
Step-by-step explanation:
According to the graph, there are vertical asymptotes at
and
. Therefore, C is correct because -3+3=0 and 7-7=0.